Answer:
124
Step-by-step explanation:
First subtract 6 to both sides.
![\sqrt[5]{249-2x} = 1](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B249-2x%7D%20%3D%201)
Then take the 5th power of both sides to remove the radical.
Which is essentially:
-2x = 1 - 249
-2x = -248
Divide both sides by -2
x = 124
And there ya go :)
Answer:
<u>y = w and ΔABC ~ ΔCDE</u>
Step-by-step explanation:
Given sin(y°) = cos(x°)
So, ∠y + ∠x = 90° ⇒(1)
And as shown at the graph:
ΔABC is aright triangle at B
So, ∠y + ∠z = 90° ⇒(2)
From (1) and (2)
<u>∴ ∠x = ∠z </u>
ΔCDE is aright triangle at D
So, ∠x + ∠w = 90° ⇒(3)
From (1) and (3)
<u>∴ ∠y = ∠w</u>
So, for the triangles ΔABC and ΔCDE
- ∠A = ∠C ⇒ proved by ∠y = ∠w
- ∠B = ∠D ⇒ Given ∠B and ∠D are right angles.
- ∠C = ∠E ⇒ proved by ∠x = ∠z
So, from the previous ΔABC ~ ΔCDE by AAA postulate.
So, the answer is <u>y = w and ΔABC ~ ΔCDE</u>
(4,-2) is point H
answer is B. second choice
To find equivalent expressions,
distribute the first one and
factor the second one.
