Hopefully this is the last one
1 answer:
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We can do anything to an equation as long as we do it to both sides
given:
square both sides
minus 3 from both sides
multiply both sides by 6
![(4+\sqrt{x+3})^2=36 square root both sides, remember to take the positive and negative roots [tex]4+\sqrt{x+3}=+/-6](https://tex.z-dn.net/?f=%284%2B%5Csqrt%7Bx%2B3%7D%29%5E2%3D36%20square%20root%20both%20sides%2C%20remember%20to%20take%20the%20positive%20and%20negative%20roots%20%5Btex%5D4%2B%5Csqrt%7Bx%2B3%7D%3D%2B%2F-6)
minus 4
square both sides
do for -4+6 and -4-6 (2 and -10)
and 
minus 3
and 
test for extraneous roots
x=97 doesn't work
the answer is x=1
given:
square both sides
minus 3 from both sides
multiply both sides by 6
minus 4
square both sides
do for -4+6 and -4-6 (2 and -10)
minus 3
test for extraneous roots
x=97 doesn't work
the answer is x=1