3. (x + 1)/4 = 3 / 6
x + 1 = 3/6 x 4 = 2
x = 1
Scale factor = 6 / 4 = 1.5
Ratio of perimeters = 2 : 3
4. x / 21 = 20 / 15
x = 20 / 15 x 21 = 28
Scale factor = 20 / 15 = 4/3
Ratio of perimeters = 3 : 4
1.Consider the system of equations. x-5y=2
3x-10y=11
(a) Jamar rewrote the first equation as –2x + 10y = –4. What justification did he have for doing this?
(b)Jamar combined the equation in Part (a) with the second equation in the system to get x = 7. Explain Jamar’s reasoning.
(c) What is the solution of the system? (d) How do you know, without graphing, that the graph of 4x – 15y = 13 passes through the point whose coordinates are the solution of the system?
Answer:
The cross section of sphere is circle
Area of cross section = 25 in²
Step-by-step explanation:
From the figure we can see a cylinder with height 8 inches and volume 200 π in³.
<u>The cross section of the cylinder looks like a circle.</u>
<u>To find the area of cross section</u>
Volume of cylinder = Cross section area * Height
200 = cross section area * 8
cross section area = 200/8
= 25 in²
Area of cross section = 25 in²
Answer:
Orion's belt width is 184 light years
Step-by-step explanation:
So we want to find the distance between Alnitak and Mintaka, which is the Orions belts
Let the distance between the Alnitak and Mintaka be x,
Then applying cosine
c²=a²+b²—2•a•b•Cosθ
The triangle is formed by the 736 light-years and 915 light years
Artemis from Alnitak is
a = 736lightyear
Artemis from Mintaka is
b = 915 light year
The angle between Alnitak and Mintaka is θ=3°
Then,
Applying the cosine rule
c²=a²+b²—2•a•b•Cosθ
c² =736² + 915² - 2×, 736×915×Cos3
c² = 541,696 + 837,225 - 1,345,034.1477702404
c² = 33,886.85222975954
c = √33,886.85222975954
c = 184.0838184897 light years
c = 184.08 light years
So, to the nearest light year, Orion's belt width is 184 light years
Answer:
Solve y=x^2+2 for x.A.B.C.D
Step-by-step explanation:
sorry lamo