Exercise 3
3z-1/10^5
3z-1/100000
X intercept: when Y = 0
Y intercept: when X = 0
Plug into equation
4x + 6(0) = 12
4x = 12, x = 3
Therefore x int = (3,0)
4(0) + 6y = 12
6y = 12, y = 2
Therefore y int = (0,2)
Plug those points then draw a line through them
Answer:
(3,2)
Step-by-step explanation:
y = 4x – 10
y = 2
Substitute the second equation into the first
2 = 4x-10
Add 10 to each side
2+10 = 4x-10+10
12 = 4x
Divide each side by 4
12/4 =4x/4
3 = x
The solution is
(3,2)
A: We want to select one person who works out three days a week. Our probability is simply 12/80 ~~ 15%
B: At least 4 days a week means 4 days, 5 days, or 6 days.
Hence, we have: (9 + 20 + 8)/80 = 46%
C: At least once a week.
Let's find out how many DO NOT work out and subtract that from our sample space. This means they must work out at least once a week.
(80 - 15)/80 = 81%
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