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slega [8]
3 years ago
13

Which equation represents the line that contains the point (-2, 9) and is perpendicular to the line y = 2x + 6?

Mathematics
2 answers:
olganol [36]3 years ago
7 0
Y=-1/2x+8

perpendicular means slope is opposite reciprocal so it would be -1/2

y=-1/2x+b
Plug in points and solve for b
B=8
sveta [45]3 years ago
7 0
Y=-1/2x+8

perpendicular means slope is opposite reciprocal so it would be -1/2

y=-1/2x+b
Plug in points and solve for b
B=8
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3/5 x 3/5 is equal to 3/5 , since 3/5 is being multiple by a value equal to 3/5 true or false ?
LenKa [72]
False, because any number multiplied by a number lower than 1 will always be less than the original number
3 0
2 years ago
When an amount of heat Q (in kcal) is added to a unit mass (kg) of a
lisov135 [29]

Answer:

The change in temperature per minute for the sample, dT/dt is 71.\overline {6} °C/min

Step-by-step explanation:

The given parameters of the question are;

The specific heat capacity for glass, dQ/dT = 0.18 (kcal/°C)

The heat transfer rate for 1 kg of glass at 20.0 °C, dQ/dt = 12.9 kcal/min

Given that both dQ/dT and dQ/dt are known, we have;

\dfrac{dQ}{dT} = 0.18 \, (kcal/ ^{\circ} C)

\dfrac{dQ}{dt} = 12.9 \, (kcal/ min)

Therefore, we get;

\dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = {\dfrac{dQ}{dt} } \times \dfrac{dT}{dQ} = \dfrac{dT}{dt}

\dfrac{dT}{dt} = \dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = \dfrac{12.9 \, kcal / min }{0.18 \, kcal/ ^{\circ} C }   = 71.\overline 6 \, ^{\circ } C/min

For the sample, we have the change in temperature per minute, dT/dt, presented as follows;

\dfrac{dT}{dt}  = 71.\overline 6 \, ^{\circ } C/min

8 0
2 years ago
Please help me with my math question!!!
charle [14.2K]

Answer:y=-1/2x+3

Step-by-step explanation:

y=-1/2x+3

Bc any slope that is the same as the line is parallel.

So if you count, 1 up and two to the left.

7 0
3 years ago
Whitney kicks a football off the ground. The height, h , in feet, of the football above the ground after t seconds is given by h
malfutka [58]

Answer:

<em>after 4seconds</em>

Step-by-step explanation:

Given the height, h , in feet, of the football above the ground after t seconds expressed by h ( t ) = − 8 t^2 + 32 t, the height of the ball on the ground is 0feet.

Substitute h(t) = 0 into the expression and calculate t;

h ( t ) = − 8 t^2 + 32 t

0 = − 8 t^2 + 32 t

8t² = 32t

8t = 32

Divide both sides by 8

8t/8 = 32/8

<em>t = 4s</em>

<em>Hence the football hits the ground after 4seconds</em>

5 0
3 years ago
What is the the answer​
timofeeve [1]

Answer: x=r^2 + 10 r + 25

7 0
2 years ago
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