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Airida [17]
3 years ago
14

Acellus

Mathematics
2 answers:
DENIUS [597]3 years ago
5 0

Answer:

angle 7

Step-by-step explanation:

olya-2409 [2.1K]3 years ago
4 0

Answer:

angle 7 angle forms a pair of alternate

exterior angles with angle 2.

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If you lift a 1 pound object 36 inches, how many joules of energy did you use?
Lady bird [3.3K]

the answer is 36 bc you divide the inches by the pound brainliest plzz god bless


6 0
3 years ago
What is the LCM(Least common multiple) of 8 and 100
Sliva [168]
The LCM is 2, Because 2*4=8 and 2*50=100 :)
8 0
3 years ago
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Find the discount on a $15 T-shirt. It is on sale for 10% off.
Lelu [443]

Answer:

$13.50 (discount price)

$1.50 (discount amount)

Step-by-step explanation:

$15 x 10% =

$15 x 0.1 = $1.50

$15 - $1.50 = $13.50

3 0
3 years ago
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Use the substitution x = et to transform the given Cauchy-Euler equation to a differential equation with constant coefficients.
Anika [276]

Answer:

\boxed{\sf \ \ \ ax^2+bx^{-10} \ \ \  }

Step-by-step explanation:

Hello,

let's follow the advise and proceed with the substitution

first estimate y'(x) and y''(x) in function of y'(t), y''(t) and t

x(t)=e^t\\\dfrac{dx}{dt}=e^t\\y'(t)=\dfrac{dy}{dt}=\dfrac{dy}{dx}\dfrac{dx}{dt}=e^ty'(x)y'(x)=e^{-t}y'(t)\\y''(x)=\dfrac{d^2y}{dx^2}=\dfrac{d}{dx}(e^{-t}\dfrac{dy}{dt})=-e^{-t}\dfrac{dt}{dx}\dfrac{dy}{dt}+e^{-t}\dfrac{d}{dx}(\dfrac{dy}{dt})\\=-e^{-t}e^{-t}\dfrac{dy}{dt}+e^{-t}\dfrac{d^2y}{dt^2}\dfrac{dt}{dx}=-e^{-2t}\dfrac{dy}{dt}+e^{-t}\dfrac{d^2y}{dt^2}e^{-t}\\=e^{-2t}(\dfrac{d^2y}{dt^2}-\dfrac{dy}{dt})

Now we can substitute in the equation

x^2y''(x)+9xy'(x)-20y(x)=0\\ e^{2t}[ \ e^{-2t}(\dfrac{d^2y}{dt^2}-\dfrac{dy}{dt}) \ ] + 9e^t [ \ e^{-t}\dfrac{dy}{dt} \ ] -20y=0\\ \dfrac{d^2y}{dt^2}-\dfrac{dy}{dt}+ 9\dfrac{dy}{dt}-20y=0\\ \dfrac{d^2y}{dt^2}+ 8\dfrac{dy}{dt}-20y=0\\

so the new equation is

y''(t)+ 8y'(t)-20y(t)=0

the auxiliary equation is

x^2+8x-20=0\\ x^2-2x+10x-20=0\\x(x-2)+10(x-2)=0\\(x+10)(x-2)=0\\ x=-10\text{ or }x=2

so the solutions of the new equation are

y(t)=ae^{2t}+be^{-10t}

with a and b real

as

x(t)=e^t\\ t(x)=ln(x)

y(x)=ae^{2ln(x)}+be^{-10ln(x)}=ax^2+bx^{-10}

hope this helps

do not hesitate if you have any questions

8 0
4 years ago
9. Solve each equation.
mixas84 [53]
It would be b; 80 because 0.2 times -80 is -16
3 0
3 years ago
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