Vertex aka max or min point is found by -b/2a in form
f(x)=ax^2+bx+c
f(x)=-1x^2+8x+20
vertex x value is -8/(2)(-1)=-8/-2=4
input back to find y value
f(4)=-(4^2)+8*4+20
f(4)=-16+32+20
f(4)=36
max (since the graph opens down) is (4,36)
axis of symmetry is the x coordinate
max is (4,36)
axis of symmetrry is x=4
Step-by-step explanation: need to find a basis for the solutions to the equation Ax = 0. To do ... From this we can read the general solution, x = ⎡. ⎢ ... two vectors are clearly not multiples of one another, they also give a basis. So ... 4.4.14 The set B = {1 − t2,t − t2,2 − 2t + t2} is a basis for P2. ... x1(1 − t2) + x2(t − t2) + x3(2 − 2t + t2)=3+ t − 6t2.
(12 x 2) + (7 x 4) - 2 would be the expression
first you multiply the 12 x 2 and the 7 x 4, you add those together and then you subtract two from your total answer.
meaning your answer would be 50
