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2 years ago

Find the quotient. Simplify if possible -6/10 + (-5/7)

Mathematics

1 answer:

Zepler [3.9K]2 years ago

5 0

Answer: The correct answer is $\frac{21}{25}$

Step-by-step explanation:

To find a quotient, we need to divide the two numbers. The equation given to us is :

$\frac{-6}{10}\div \frac{-5}{7}$

To Simplify the above equation and finding out the quotient, we need to divide the above equation, we get:

$\Rightarrow \left(\frac{\frac{-6}{10}}{\frac{-5}{7}}\right)$

Taking the reciprocal of the denominator and multiplying it with the numerator, we get:

$\Rightarrow \frac{-6}{10}\times \frac{7}{-5}\\\\\Rightarrow \frac{42}{50}\\\\\Rightarrow \frac{21}{25}$

Hence, the correct answer is $\frac{21}{25}$

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Dima020 [189]

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3 years ago

(B^2)(B^4) Answer choices B^8 B^6 B^2 2b^6

ruslelena [56]

Answer:

Step-by-step explanation:

(B^2)(B^4) = B^(2+4)= B^6

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2 years ago

PLEASE HELP-

Deffense [45]

Answer:

1492.88

Step-by-step explanation:

V = πr^2 h/3

3.14 × 18^2

3.14 × 324 = 1017.36

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2 years ago

Which ordered pairs lie on the graph of the exponential function f(x)=−3^(x−1) +2 Select each correct answer.

katrin [286]

<h3>Answer:</h3>

(1, 1), (4, -25)

<h3>Step-by-step explanation:</h3>

You can evaluate the function to see.

f(-1) = -3^(-1-1)+2 = -3^(-2)+2 = -1/9 +2 ≠ 2

f(1) = -3^(1-1) +2 = -1 +2 = 1

f(0) = -3^(0-1) +2 = -1/3 +2 ≠ 0

f(4) = -3^(4 -1) +2 = -27 +2 = -25

_____

Or, you can graph the points and the curve.

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3 years ago

A tank with a capacity of 1000 L is full of a mixture of water and chlorine with a concentration of 0.02 g of chlorine per liter

faltersainse [42]

At the start, the tank contains

(0.02 g/L) * (1000 L) = 20 g

of chlorine. Let c (t ) denote the amount of chlorine (in grams) in the tank at time t .

Pure water is pumped into the tank, so no chlorine is flowing into it, but is flowing out at a rate of

(c (t )/(1000 + (10 - 25)t ) g/L) * (25 L/s) = 5c (t ) /(200 - 3t ) g/s

In case it's unclear why this is the case:

The amount of liquid in the tank at the start is 1000 L. If water is pumped in at a rate of 10 L/s, then after t s there will be (1000 + 10t ) L of liquid in the tank. But we're also removing 25 L from the tank per second, so there is a net "gain" of 10 - 25 = -15 L of liquid each second. So the volume of liquid in the tank at time t is (1000 - 15t ) L. Then the concentration of chlorine per unit volume is c (t ) divided by this volume.

So the amount of chlorine in the tank changes according to

$\dfrac{\mathrm dc(t)}{\mathrm dt}=-\dfrac{5c(t)}{200-3t}$

which is a linear equation. Move the non-derivative term to the left, then multiply both sides by the integrating factor 1/(200 - 5t )^(5/3), then integrate both sides to solve for c (t ):

$\dfrac{\mathrm dc(t)}{\mathrm dt}+\dfrac{5c(t)}{200-3t}=0$