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3 years ago

15

The angles of a quadrilateral measure 80, 100, 100, 80 in this order what kind of quadrilateral has this shape what attributes h

elp you solve the promblem

1 answer:

Harrizon [31]3 years ago

8 0

Answer:

Isosceles trapezoid

Step-by-step explanation:

-An isosceles trapezoid is also sometimes called a convex quadrilateral.

-It properties include:

A line of symmetry can often bisects a pair of opposite sides.

It has to obtuse alternating with each other after which a pair of acute angles alternate with each other i.e 80°, 80°,100°,100°
It has a trapezoidal shape which by definition has a two pair of parallel sides.
The angles on it's base or ceiling are equal hence the name Isosceles Trapezoid.

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Please help me with this. I'm stuck

Anon25 [30]

Answer:

Step-by-step explanation:

7 choose 2 or

=7! / (7-2)!

=7*6*5*4*3*2*1 / 5*4*3*2*1

=7*6

=42

8 0

3 years ago

Read 2 more answers

Solve using Fourier series.

Olin [163]

With $2L=\pi$ , the Fourier series expansion of $f(x)$ is

$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L$
$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx$

where the coefficients are obtained by computing

$\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx$
$\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx$

$\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx$

$\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx$

You should end up with

$a_0=0$
$a_n=0$
(both due to the fact that $f(x)$ is odd)
$b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)$

Now the problem is that this expansion does not match the given one. As a matter of fact, since $f(x)$ is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of $f(x)$ , which is to say we're actually considering the function

$\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3$

and enforcing a period of $2L=2\pi$ . Now, you should find that

$\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)$

The value of the sum can then be verified by choosing $x=0$ , which gives

$\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)$
$\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots$

as required.

5 0

3 years ago

Express sin A,cos A and tan A as ratios

OverLord2011 [107]

Answer:

Part A) $sin(A)=\frac{2\sqrt{42}}{23}$

Part B) $cos(A)=\frac{19}{23}$

Part C) $tan(A)=\frac{2\sqrt{42}}{19}$

Step-by-step explanation:

Part A) we know that

In the right triangle ABC of the figure the sine of angle A is equal to divide the opposite side angle A by the hypotenuse

so

$sin(A)=\frac{BC}{AB}$

substitute the values

$sin(A)=\frac{2\sqrt{42}}{23}$

Part B) we know that

In the right triangle ABC of the figure the cosine of angle A is equal to divide the adjacent side angle A by the hypotenuse

so

$cos(A)=\frac{AC}{AB}$

substitute the values

$cos(A)=\frac{19}{23}$

Part C) we know that

In the right triangle ABC of the figure the tangent of angle A is equal to divide the opposite side angle A by the adjacent side angle A

so

$tan(A)=\frac{BC}{AC}$

substitute the values

$tan(A)=\frac{2\sqrt{42}}{19}$

8 0

3 years ago

1) any letters can change into an a

Dimas [21]

CAC can be changed into CAAC. This is because the first rule says that any letter can change into an A so
CAC=CAA
The last condition says that when you double , you have to double all letters,
Since A has been doubled,C needs to be doubled too.So:
CAA=CAAC

4 0

3 years ago

What do you think the value of represents in the function? How can you predict what the graph of a quadrati function will look l

allochka39001 [22]

Answer:

Step-by-step explanation:

Parts of the question are missing.

y = a(x-h)² + k is a vertical parabola.

If a is positive, the parabola opens upwards.

If a is negative, the parabola opens downwards.

The vertex is at (h, k)

7 0

2 years ago