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SOVA2 [1]
2 years ago
14

Graph f(x) = 3 sin (1/2x) - 5 Use 3.14 for (pi sign) (idk where to graph is at)

Mathematics
1 answer:
timurjin [86]2 years ago
8 0

Answer:

The graph of the function is attached in the figure a.

Step-by-step explanation:

Considering the expression

f\left(x\right)=3\sin \left(\frac{1}{2}x\right)-5

As we have to determine the graph of the function

  • f\left(x\right)=3\sin \left(\frac{1}{2}x\right)-5
  • Using 3.14 for pi

The graph of the function is attached in the figure a.

Please check the attached figure a to visualize the graph.

Hope if helps.

Keywords: graph, sin function

Learn more about graph and sin function from brainly.com/question/12651716

#learnwithBrainly

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Answer:

y = -3

Step-by-step explanation:

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Write the equation of the line in point-slope form that goes through the points (0, 1) and (2, 7)
laiz [17]

Answer:

point - slope form

 y - 1 = 3 (x-0)

Step-by-step explanation:

<u><em>step(i):-</em></u>

Given points are (0,1) and (2,7)

The slope of the line

     m = \frac{y_{2}-y_{1}  }{x_{2} -x_{1} }

    m = \frac{y_{2}-y_{1}  }{x_{2} -x_{1} } = \frac{7-1}{2-0} = \frac{6}{2}  = 3

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<u><em>Step(ii):-</em></u>

point -slope form

   y - y₁ = m(x-x₁)

Equation of the straight line passing through the point (0,1) and having slope 'm' = 3

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  y -1 = 3x

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Equation of the straight line passing through the point (0,1) and having slope 'm' = 3 is 3x -y +1=0

4 0
2 years ago
A train leaves San Diego at 1:00 pm. A second train leaves the same city in the same direction at 3:00 pm. The second train trav
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Answer:

The speed of the first train is 45 mph and the speed of the second train is 75 mph

Step-by-step explanation:

Let x represent the speed of the first train in mph. Since the second train, is 30 mph faster then the first, therefore the speed of the second train is (x + 30).

The first train leaves at 1:00 pm, therefore at 6:00 pm, the time taken is 5 hours. Therefore the distance covered by the first train at 6:00 pm = x mph * 5 hours = 5x miles

The second train leaves at 3:00 pm, therefore at 6:00 pm, the time taken is 3 hours. Therefore the distance covered by the second train at 6:00 pm = (x + 30) mph * 3 hours = (3x + 90) miles

Since the second train overtakes the first at 6:00 pm, hence:

3x + 90 = 5x

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Therefore the speed of the first train is 45 mph and the speed of the second train is 75 mph (45 mph + 30 mph).

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