Basically here all you want to do it substitute the values x=1 and x=2 for the given function. Use your slope formula $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1} }$ .

Do same for x=3 and x=4

You next divide plug in values in to this expression:

$\frac{Slope of B}{Slope of A}$

6 0

4 years ago

I forgot how to find the area of the inside of the triangle to find the volume.

enot [183]

Maybe use a ruler To find the area and add them together to fin the volume.

3 0

4 years ago

In a triangle ABC, AD is drawn perpendicular to BC. <br> Prove that AB2 - BD2 = AC2 - CD2.

Finger [1]

Answer:

Given: In triangle ABC , AD is drawn perpendicular to BC.

Since AD is drawn perpendicular to BC, it creates two right triangles: ADB and ADC.

Prove that: $AB^2-BD^2 = AC^2-CD^2$

Pythagoras triangle for right angle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs.

In a right angle triangle ADB;

$AD^2+BD^2 = AB^2$ [By Pythagoras theorem]

$AD^2= AB^2-BD^2$ .......[1]

Now, in right angle triangle ADC;

$AD^2+CD^2 = AC^2$ [By Pythagoras theorem]

or we can write this as;

$AD^2= AC^2-CD^2$ ......[2]

Substituting the equation [1] in [2] we get;

$AB^2-BD^2 =AC^2-CD^2$ hence proved!

5 0

3 years ago