Identify each x-value at which the slope of the tangent line to the function f(x) = 0.2x^2 + 5x − 12 belongs to the interval (-1
2 answers:
Answer:
Step-by-step explanation:
Hello, the slope of the tangent is the value of the derivative.
f'(x) = 2*0.2x + 5 = 0.4x + 5
So we are looking for
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Answer:
Step-by-step explanation:
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Answer:
x = 30°, y = 39°
Step-by-step explanation:
53 + 58 + y + x = x + 150
=> 53 + 58 + y = 150
=> y = 150 - 53 - 58
=> y = 39°
x + 150 = 180
=> x = 180 - 150 = 30°
The answer is y= 1/2x + 2
Answer:
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Do 7.50 times 4 and you get 30 so it’s 30
X^2-13x+30
x^2-10x-3x+30
x(x-10)-3(x-10)
(x-3)(x-10)
so two zeors are 3 and 10 !!