Question

Identify each x-value at which the slope of the tangent line to the function f(x) = 0.2x^2 + 5x − 12 belongs to the interval (-1, 1).

Answer 1

Answer:

Step-by-step explanation:

Hello, the slope of the tangent is the value of the derivative.

f'(x) = 2*0.2x + 5 = 0.4x + 5

So we are looking for

$-1\leq f'(x) \leq 1 \\ \\ -1\leq 0.4x+5 \leq 1 \\ \\ -1-5=-6\leq 0.4x \leq 1-5=-4 \\ \\ \dfrac{-6}{0.4}\leq 0.4x \leq \dfrac{-4}{0.4} \\\\ \boxed{-15 \leq x\leq -10}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer 2

Answer:

Step-by-step explanation: