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OlgaM077 [116]
3 years ago
13

Help please Algebra 2 B

Mathematics
1 answer:
avanturin [10]3 years ago
7 0
Vertical asymptotes can be found from the denominator, because denominators cannot be equal 0.
x²-16=0
(x-4)(x+4)=0
x=4, x=-4 
x cannot be 4 or -4,
So vertical asymptotes
x=4 , x=-4

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Answer:

  one solution is (0, -2)

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The line y = -x is the boundary of the solution space of the first inequality. The less-than symbol (<) tells you that the line will be dashed and the shading will be below it. The line has a slope of -1 and goes through the y-intercept point (0, 0).

The line y = x - 2 is the boundary of the solution space for the second inequality. The less-than-or-equal-to symbol (≤) tells you the line will be solid (or equal to) and the shading will be below it (less than). The line has a slope of +1 and goes through the y-intercept point (0, -2).

The area of the graph where the shadings overlap is the solution space for the system of inequalities. Any point in that area will do, including points on the solid line where y < -x. (0, -2) is one such point.

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