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dem82 [27]
3 years ago
10

Assume a significance level of

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
3 0

Answer:

Part a: The correct answer is A, reject H0 because p value is less than \alpha. Part B: The correct answer is C, the percentage of adults that would erase their personal information online if they could is more than 51%.

Step-by-step explanation:

part a. The essential idea of hypothesis testing in statistics is to evaluate the probability p (p value) of some representative parameter, compared to a level of likelihood that is set before starting the test (\alpha). In this case, we are interested in a level of likelihood \alpha=0.05, which means that if the probability of the parameter is less than 5%, we will reject the hypothesis that this parameter is representing, since it's so unlikely. Of course, the significance level is arbitrary and must be payed attention, according to the particular situation. Therefore, the correct anser is A.

part b. Since we rejected the hypothesis to a 5% significance level, we reject the fact that less than 51% of adults would erase their personal information online if they could. This is equivalent to saying that a percentage of adults equal to or more than 51% would erase their personal information if they could, which is answer C.

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<u>Solution:</u>

Given that , In a certain function, y varies directly with x

And x = 8 when y = 6,

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Now, from the given information,

\begin{array}{l}{y \alpha x} \\\\ {y=c x \rightarrow(1)}\end{array}

where c is the proportionality constant

\begin{array}{l}{\text { Now, substitute } x=8 \text { and } y=6 \text { in }(1)} \\\\ {\rightarrow 8=c(6) \rightarrow c=\frac{8}{6}} \\\\ {\rightarrow c=\frac{4}{3}} \\\\ {\text { Then, }(1) \rightarrow x=\frac{4}{3} y} \\\\ {\text { So, when } y=9} \\\\ {\rightarrow x=\frac{4}{3}(9)} \\\\ {\rightarrow x=4 \times 3} \\\\ {\rightarrow x=12}\end{array}

Hence, x value is 12 when y value is 9

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