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vaieri [72.5K]
2 years ago
9

An object is completely submerged in a liquid of density 0.65 grams per cubic centimeter at a depth of 3 meters. What is the tot

al pressure on the object? State your answer in atmospheres. (Round your answer to to three significant digits)
Mathematics
1 answer:
3241004551 [841]2 years ago
3 0
The pressure due to the depth in a liquid can be calculated as:
P = ρgh; ρ is the density in kg/m³, g is the acceleration due to gravity in m/s² and h is the depth in the fluid.
ρ = 0.65 g/cm³ = 650 kg/m³
P = 650 x 9.81 x 3
= 19100 Pascals
Pressure in atm = 19100/101325 atm
= 0.188 atm
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the first box measures 18 inches by 8 inches by 15 inches. the second box is 10 inches tall and the area of the base measures 19
Mandarinka [93]

Answer:

  Box 1 has the greater volume, by 200 in³

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The largest of two volumes can be found by computing each volume and comparing the results.

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<h3>Box 2</h3>

The volume is computed from area and height by ...

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<h3>Comparison</h3>

The units of the two volumes are the same, so we can decide which is larger by comparing the numbers. Box 1 has a volume that is more than 2000 in³, and Box 2 has a volume that is less than 2000 in³.

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In order to find which <u>expression</u> is <u>equivalent</u> to \sqrt[4]{x^{10}}, <u>simplify</u> all given expressions:

0.

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x^2(\sqrt[4]{x^2})=x^2\cdot x^{\frac{2}{4}}=x^2\cdot x^{\frac{1}{2}}=x^2\cdot x^{0.5}=x^{2.5}.

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x^{2.2}.

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x^3(\sqrt[4]{x} )=x^3\cdot x^{\frac{1}{4}}=x^3\cdot x^{0.25}=x^{3.25}.

4.

x^5.

Therefore,

Answer: correct choice is A

7 0
3 years ago
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