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dem82 [27]
3 years ago
14

Help me with this please!!!!!!!!!!

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
5 0

Answer:

B)  (8, 0) and (-4,0)

Step-by-step explanation:

x-intercept when y = 0

so

x^2 - 4x - 32 = 0

Factors

(x - 8)(x + 4 ) = 0

x - 8 = 0; x = 8

x + 4 = 0; x = -4

(8, 0) and (-4,0)

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Which pair of rectangles is similar?<br><br>​
MariettaO [177]
The answer is C. When multiplying the smaller rectangle by 2 on both sides, you will get the bigger rectangle’s measurements
5 0
3 years ago
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Which equation does NOT represent a proportional relationship between two variables with the constant of proportinality of? 1/2
Dimas [21]

Answer:

(D) y=x+\frac{1}{2}

Step-by-step explanation:

Two variables x and y are proportionally related  if they can be written in the form y=kx, where k is the constant of proportionality.

From the given options, if k=\frac{1}{2}

(B)y=\frac{1}{2}x is of the form y=kx

(C)y=\frac{3}{6}x is of the form y=kx with k=\frac{1}{2} as \frac{3}{6}=\frac{1}{2} in its lowest form.

(C)y=0.5x is of the form y=kx with k=\frac{1}{2} as 0.5=\frac{1}{2} in fractional form.

On the Contrary,

In Option D, y=x+\frac{1}{2} does not represent a proportional relationship between x and y. The constant of proportion is supposed to be a product of x.

6 0
3 years ago
Determine the coordinator of the point<br>of intersection of lines<br>3x-2y=13 and 2y+x+1=0​
finlep [7]

Answer:

(3,-2)

Step-by-step explanation:

Given equations of line

3x-2y=13

2y+x+1=0​

=> x = -1 -2y

Point of intersection will coordinates where both equation have same value of (x,y)

top get that we have to solve the both equations by using method of substitution of simultaneous equation.

using this value of x in 3x-2y=13, we have

3(-1-2y) -2y = 13

=> -3 -6y-2y = 13

=> -8y = 13+3 = 16

=> y = 16/-8 = -2

x = -1 - 2y = -1 -2(-2) = -1+4= 3

Thus, point of intersection of line is (3,-2)

3 0
3 years ago
Value of the expression 9.7+(- 5.4)
BARSIC [14]
4.3 I believe. That's the answer I got.
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3 years ago
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HELP ME PLZZZ!!!! URGENT!!!​
finlep [7]

Answer:

Step-by-step explanation:

Given equation is,

x² + (p + 1)x = 5 - 2p

x² + (p + 1)x - (5 - 2p) = 0

x² + (p + 1)x + (2p - 5) = 0

Properties for the roots of a quadratic equation,

1). Quadratic equation will have two real roots, discriminant will be greater than zero. [(b² - 4ac) > 0]

2). If the equation has exactly one root, discriminant will be zero [(b² - 4ac) = 0]

3). If equation has imaginary roots, discriminant will be less than zero [(b² - 4ac) < 0].

Discriminant of the given equation = (p+1)^2-4(1)(2p-5)

For real roots,

(p+1)^2-4(1)(2p-5)>0

p² + 2p + 1 - 8p + 20 > 0

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For all real values of 'p', given equation will be greater than zero.

5 0
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