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tankabanditka [31]
2 years ago
13

(45x + 52y) + (-5x + 40y) A.50x + 92y B.40x + 92y C.40x + 12y D.50x + 12y

Mathematics
1 answer:
vesna_86 [32]2 years ago
8 0
= 45x + 52y -5x + 40y
= 45x - 5x + 52y + 40y
= 40x + 92y

the answer is B
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\frac{-6xy^{3}z^5}{-36x^{2}y^{2}z^4}

First cross out the -6 and -36. Six will go into 6 one time and 6 will go into -36 six times so we have the following after crossing out.

\frac{-6xy^{3}z^5}{-36x^{2}y^{2}z^4}
\frac{xy^{3}z^5}{6x^{2}y^{2}z^4} <---After crossing out

Next cross out the x / x^2 which will give us the following:
\frac{xy^{3}z^5}{6x^{2}y^{2}z^4} 
\frac{y^{3}z^5}{6xy^{2}z^4} <---After crossing out

Now cross out the y^2 / y^3
\frac{y^{3}z^5}{6xy^{2}z^4}
\frac{yz^5}{6xz^4} <----After crossing out

All that is left is to cross out the z^5 / z^4 and we are done.
\frac{yz^5}{6xz^4}
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3 years ago
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