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nasty-shy [4]
3 years ago
9

-3 + 10y – 8y + 4 – 6 + y simplify

Mathematics
2 answers:
Darya [45]3 years ago
7 0

Answer:

3y - 5

Step-by-step explanation:

We combine like terms. The y terms are 10y, -8y and y which combine to 3y. Think of it like having 10 items, take away 8 items but then add on 1 more. So we'd have 10-8+1 = 2+1 = 3 items overall. Replace "Items" with y and we have 10y-8y+1y = (10-8+1)y = 3y

The other terms are constant terms as they dont have any variables attached to them. These terms are -3, 4 and -6 which combine to -3+4-6 = 1-6 = -5

In summary, the y terms combine to 3y while the constant terms combine to -5. Put together, the fully simplified answer is 3y-5

Harman [31]3 years ago
3 0
The answer is 3y-5.hope this helps

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6. (4.2.12) Of the items manufactured by a certain process, 20% are defective. Of the defective items, 60% can be repaired. a. F
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Answer:

(a) Probability that a randomly chosen item is defective and cannot be repaired is 8%.

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Step-by-step explanation:

We are given that of the items manufactured by a certain process, 20% are defective. Of the defective items, 60% can be repaired.

Let Probability that item are defective = P(D) = 0.20

Also, R = event of item being repaired

Probability of items being repaired from the given defective items = P(R/D) = 0.60

<em>So, Probability of items not being repaired from the given defective items = P(R'/D) = 1 - P(R/D) = 1 - 0.60 = 0.40 </em>

(a) Probability that a randomly chosen item is defective and cannot be repaired = Probability of items being defective \times Probability of items not being repaired from the given defective items

              = 0.20 \times 0.40 = 0.08 or 8%

So, probability that a randomly chosen item is defective and cannot be repaired is 8%.

(b) Now we have to find the probability that exactly 2 of 20 randomly chosen items are defective and cannot be repaired.

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 20 items

            r = number of success = exactly 2

           p = probability of success which in our question is % of randomly

                  chosen item to be defective and cannot be repaired, i.e; 8%

<em>LET X = Number of items that are defective and cannot be repaired</em>

So, it means X ~ Binom(n=20, p=0.08)

Now, Probability that exactly 2 of 20 randomly chosen items are defective and cannot be repaired is given by = P(X = 2)

   P(X = 2) = \binom{20}{2} \times 0.08^{2} \times  (1-0.08)^{20-2}

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                 = 0.2711

<em>Therefore, probability that exactly 2 of 20 randomly chosen items are defective and cannot be repaired is </em><em>0.2711.</em>

             

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Answer:

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