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dangina [55]
4 years ago
7

A security code consists of 9 digits (0–9), and a digit may not be used more than once. How many possible security codes are the

re?
Mathematics
2 answers:
ololo11 [35]4 years ago
4 0

Answer:

a

Step-by-step explanation:

Firlakuza [10]4 years ago
4 0

Answer: 362880 (?)

Step-by-step explanation:

I believe this question is asking for a permutation, in which I plugged it into my graphing calculator as nPr(9,9) and got that answer.

You might be interested in
What is the interquartile for this set of data? 11,19,35,42,60,72,80,85,88
exis [7]

Answer:

55.5

Step-by-step explanation:

find the median - in this case it's 60

then group the upper and lower halves of the data:

(11, 19, 35, 42) 60 (72, 80, 85, 88)

now we find the medians of those sets:

35 + 19/2 = 54/2 =27

80 + 85/2 = 165/2 = 82.5

then subtract those two medians to find the interquartile:

82.5 - 27 = 55.5

4 0
3 years ago
25 POINTS. I need help on my CALC hw. help me.. please. I don't get it.
olya-2409 [2.1K]
Well, what I can make out is.

"20% of the drug present in the preceding time...", is mostly mumble jumble, in short is just saying, the patient took a pill, then before taking another pill, the previous pill isn't really gone from the body stream, is there still, 20% of it, so by the time the patient drops another pill in the following day as prescribed, she's dropping 500mg of the drug, which is 100% of the drug, but besides that, she already has 20% of the drug from the pill she took the previous time, the day before, so, from yesterday.

a)

how much of the drug is there when she takes another pill?

well, 20% of 500mg is just 100mg 0.2 * 500

so, she's dropping 500mg today, and she has in her body stream 100mg(20%) from the one she took yesterday, so her body will have then 500 + 100 milligrams of the drug.

b)

\bf Q_n=\stackrel{previous~term}{\textit{amount of the drug yesterday}}\\\\
Q_{n+1}=\stackrel{next~term}{\textit{amount of the drug today}}
\\\\\\
Q_{n+1}=Q_n+20\%~of~Q_n\implies Q_{n+1}=Q_n+0.2Q_n
\\\\\\
Q_{n+1}=1.2Q_n\impliedby \textit{now, this is fine, but this is a \underline{sum}}
\\\\\\
Q_{n+1}=2Q_n-80\%~of~Q_n\implies Q_{n+1}=2Q_n-0.8Q_n

now, the second equation there, is fine too, is just that it is a difference, but the result is the same 1.2 or 120% of the drug.

in essence the difference equation is just saying, "ok, grab two pills and then subtract 80% of one pill, that's what your body has right after taking the next pill".
6 0
3 years ago
I am not sure how to do this,
maks197457 [2]

Answer:

I won't tell you the answer but ill tell you how to do it.

Step-by-step explanation:

First, you have to cut the shape, so make one triangle and one square. Then, subtract the ten to the 14 to get 4 so you know how wide the triangle is. Next you work on only the square...for now. You multiply W*H (width times height) then you get a number(10*9). Next you move on to the triangle, You multiply 4 (the number you got by subtracting 10 from 14) by 3 b*h (base times height). When ever dealing with a triangle always divide your answer by two. Once you have the area of the square and the triangle you add both of those together to get your final answer.


<h3>Please award me brainliest</h3>
6 0
3 years ago
Please help!!! I don’t really understand this at all
olga_2 [115]
- line CD is perpendicular to segment AB
- point M is the midpoint of segment AB
6 0
3 years ago
Read 2 more answers
Polygon ABCD is dilated by a scale factor of 2 with the center of dilation at the origin to create polygon A′B′C′D′. If the endp
OverLord2011 [107]

Answer:

34

Step-by-step explanation:

A = (0, -7)

A' = (0, -14)

B = (8, 8)

B' = (16, 16)

Distance formula = \sqrt{({x_{2}- x_{1}})^{2} + ({y_{2}- y_{1}})^{2}}

= \sqrt{16^{2} + 30^2}

= \sqrt{1156}

= 34

7 0
3 years ago
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