Part A: Yes, because no input yields more than output values.
Part B: If f(x)= 5x-21, switch the x's to 11.
f(11)=5(11)- 21. 5 times 11 equals 55, then minus by 21. 55- 21= 34.
In the table, y=8 and x=11, but in the function, y=34 and x=11.
Part C: I have to make sure to plug in 99 for f(x).
f(x)= 5x -21, which basically is 99= 5x -21.
Add 21 to both sides. 99+21 = 5x -21+21.
99 plus 21 =120, which 120= 5x.
Divide 120 by 5 and divide 5x by 5.
The answer will be 24