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3 years ago

Log 3(x+5)- log 3(x-3) = 2

Mathematics

2 answers:

inessss [21]3 years ago

7 0

Answer:

x = 4

Step-by-step explanation:

solate the variable by dividing each side by factors that don't contain the variable.

iogann1982 [59]3 years ago

4 0

Here is your answer...
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Jaxson is throwing a pizza party. He has 1\tfrac{1}{4}1 4 1 pounds of cheese available and he needs \tfrac{1}{8} 8 1 pound o

yKpoI14uk [10]

Answer:

10 pizzas

Step-by-step explanation:

Jaxson is throwing a pizza party. He has 1\tfrac{1}{4}1 4 1 pounds of cheese available and he needs \tfrac{1}{8} 8 1 pound of cheese to make each pizza. How many pizzas can he make?

We can interprete the above question as:

1/8 pounds of cheese = 1 pizza

1 1/4 pounds of cheese = x pizzas

Cross Multiply

1/8 × x = 1 1/4 × 1

x = 1 1/4 ÷ 1/8

x = 5/4 ÷ 1/8

x = 5/4 × 8/1

x = 10 pizzas

3 0

3 years ago

Solve the system of equations using matrices. Use the Gauss- Jordan elimination method And find a solution set

KATRIN_1 [288]

$\begin{gathered} x+y+z=4 \\ x-y-z=0 \\ x-y+z=8 \\ \text{The system using matrix is} \\ \begin{bmatrix}{1} & {1} & {1}, & {4} \\ {1} & {-1} & {-1,} & {0} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix}\rightarrow F2=F2-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix} \\ \rightarrow F3=F3-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F2=-\frac{1}{2}F2 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F3=F3+2F2=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {2,} & {8}{}{}\end{bmatrix}\rightarrow F3=\frac{1}{2}F3 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F2=F2-F3=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \rightarrow F1=F1-F3=\begin{bmatrix}{1} & {1} & {0}, & {0} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F1=F1-F2 \\ =\begin{bmatrix}{1} & {0} & {0}, & {2} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \text{Therefore, the solution is }x=2,\text{ y=-2 and z=4} \end{gathered}$

6 0

1 year ago

HELP ON THESE 2 QUESTIONSS PLSSSS

GaryK [48]

Answer:

1) the third equation or X/2=2.0

2) 20 bucks

Step-by-step explanation:

for number 1 just plug in the x hi 4 and try to solve it

2) just calculate unit rate by 120/6=20

6 0

3 years ago

Find the 14th term of the following geometric sequence.<br> 4, 8, 16, 32, ...

xz_007 [3.2K]

Answer:

65536

Step-by-step explanation:

multiply each term by 2 until you get to the 14th term. the 14th term is 65536

4 0

3 years ago

Read 2 more answers

Which of these shows the result of using the first equation to substitute for y in the second equation, then combining like term

katen-ka-za [31]

Answer:

D. 8x=16

Step-by-step explanation:

If y=2x, then

2x+3y=16

2x+3(2x) =16

2x +6x=16

8x=16

5 0

3 years ago