If sin x = 0.5, what does sin (-x) equal ?

The prism shown has a volume of 35 cm.

Vesna [10]

Answer:

1.25cm

Step-by-step explanation:

Complete question:

The prism has a volume of 35 cm cubed workout h, the height of the triangular cross section

length=7cm

width = 4cm

The volume of the prism is expressed as;

Volume = Base Area * Height

Given

Volume of the prism = 35cm^3

Base Area = length * width

Base Area = 7cm * 4cm

Base Area = 28cm^2

Substitute the given values into the formula

35 = 28* Height

Cross multiply

35 = 28 * Height

35 = 28 Height

Height = 35/28

Height = 1.25cm

Hence the height of the triangular cross section is 1.25cm

7 0

3 years ago

Stem question, can you plz tell me 3 types of natural water vapor other that steam, fog, and clouds, thanks.

alisha [4.7K]

Answer:

Smoke, Condensation, mist

Step-by-step explanation:

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5 0

3 years ago

HH represents the height of the tree (in centimeters), t tt years since Renata moved in. H = 210 + 33 t H=210+33tH, equals, 210,

Jet001 [13]

Answer:

Therefore the rate of growth of the tree is 33 cm/ yr.

Step-by-step explanation:

Given that,

The height of the tree is

H= 210 +33t

Here H represent the height of tree in cm and t is time in year.

The rate of growth is the first order derivative of the H with respect to time.

i.e The rate of growth $=\frac{dH}{dt}$

∴H= 210 +33t

Differentiating with respect to t

$\frac{dH}{dt} =0 +33$

$\Rightarrow \frac{dH}{dt}=33$

Therefore the rate of growth of the tree is 33 cm/ yr.

7 0

3 years ago

List and explain the elements that make up the structure of a fugue, then list and explain at least four techniques Bach utilize

mina [271]

Answer:

The fugue begins with an exposure. After the exhibition the alternative composer between episodes and presentations of the subject. In each fugue this scheme is developed in a varied way according to the invention and the needs of the composer.

Step-by-step explanation:

The elements that make up a musical fugue are:

The exhibition: It begins with one of the voices presenting the subject (name given to the theme on which a fugue is based). A second voice continues with the answer. The other voices continue alternately between subjects and responses. The exhibition concludes once all the voices have presented the subject or the answer.

While the second voice presents the answer the first voice makes a counterpoint to this answer. Similarly, when the third voice enters, the first two accompany it with other counterpoints. This counterpoint can be called counterpoint or free counterpoint. It is called a countersubject when it appears next to the answer. When the counterpoint is different in each presentation it is known as a free counterpoint.

The final section of the fugue begins when the subject returns to the initial hue of the fugue and from here to the end of the work. This ending is usually formed in several measures added to the main structure. This conclusion is the coda.

In the first place, he must remember that Bach was a self-taught, he was trained alone and specifically by the study of music itself, by the observation and analysis of other people's compositions, very often of poor significance in front of his own and that he copied, however, of his handwriting. The pedagogical activity of Bach and what he taught: "We must make the fugue of the subject", this means that each subject requires his fugue. Bach added another teaching, "voices must not enter without having something to say, or call before they have said everything they have to say," which means that they have voices should not speak for speaking and that they have no obligation to be always present.

In conclusion, Bach did not give any norm about the fugue, not least in terms of the genre of procedures for cases where this kind of compositions could be applied, leaving subjects free to perform this type of music.

6 0

3 years ago

Resuelve los problemas de una bodega que exporta tomates al extranjero

Dovator [93]

Answer:

1. 34.42 Toneladas

2. 28.640 toneladas

3. 38 toneladas

4. $\frac{15}{10}$ o $1\frac{5}{10}$

5. $\frac{16}{6}$ o $2\frac{4}{6}$

6. $\frac{8}{4}$ o $2$

1.1 Solucioné el problema convirtiendo el .25 en fracción.

2.1 Conviertes el denominador en el mismo buscando el minimo comun multiplo

3.1 0.099

$\frac{1}{4}$

$\frac{1}{3}$

$\frac{2}{3}$

0.7

0.75

1.1

$\frac{3}{2}$

Step-by-step explanation:

Acuerdate que para solucionar las fracciones mixtas solo tienes que dividir el denominador al nominador, por ejemplo en si tienes $\frac{10}{3}$ entonces el 3 cabe 3 veces en el 10, y sobra 1, entonces quedamos que en mixta la fracción sería $3\frac{1}{3}$

Entonces una vez que recordamos eso, podemos resolver los problemas de fracciones sin ningún problema vamos a resolver la número 4:

$\frac{8}{10} +\frac{7}{10}$

Como el denominador es igual, sólo sumamos el nominador:

$\frac{8+7}{10}$

$\frac{15}{10}$

Cómo el 10 cabe 1 vez en el 15, tenemos un entero y sobran 5:

$1\frac{5}{10}$

5 0

3 years ago