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Ksivusya [100]
3 years ago
9

After spending $43 on groceries and $19 on a book, Mrs. Groom had $16 left. How much money did Mrs. Groom have to begin with?

Mathematics
2 answers:
Iteru [2.4K]3 years ago
5 0
If you do $43+$19+$16 that would equal $78 in total. This was an addition question.
vitfil [10]3 years ago
4 0
Do $43+19+16=$78

He started with $78
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The answer to this question is actually just simple arithmetic. At the end of the first round, Katie and Jenny will have 100 points each. In the second round, Katie and Jenny will have 200 points and 300 points respectively. At the third round, Katie and Jenny will both have 400 points. At the fourth round, Katie and Jenny will have 800 and 600 points respectively. So the turn at which Katie will have more points than Jenny is the fourth round since Katie has 800 and Jenny has 600. 
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3 years ago
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What is the equation of the line that passes through the point (3,-7) and has a slope of -4/3?
Gemiola [76]

Answer:

4x + 3y + 9 = 0

Step-by-step explanation:

When a slope of a line and a point passing through it is given then we use slope - one point form to determine the equation of the line.

It is given by:

                      $ (y - y_1) = m (x - x_1) $

where $m$ is the slope of the line and

           $ (x_1, y_1) $ is the point passing through it.

Here, $ m = \frac{-4}{3} $ and $ (x_1 , y_1) = (3 , -7) $.

Substituting in the formula y +  7 = \frac{-4}{3} (x - 3)

$ \implies 3y + 21 = -4x + 12 $

$ 4x + 3y + 9 = 0 $

3 0
3 years ago
Is y=3/2x 6 a non linear or linear equation?
Brilliant_brown [7]
This is a linear equation as when you graph it you get a line
7 0
3 years ago
What are the open intervals?
olga2289 [7]
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6 0
3 years ago
What is the probability of choosing a pair that contains ONLY cards labeled with the letters B, C, or F?
Nezavi [6.7K]

Answer:

Pr = \frac{1}{6}

Step-by-step explanation:

Given

Cards = \{A,B,C,D,E,F\}

r = 2 --- selection

Required

Probability of choosing a pair with only B, C and F

The total selection is: 36

This is calculated as thus:

First = 6 --- First selection can be any of the 6 cards

Second = 6 --- Second selection can be any of the 6 cards [No restriction]

So, we have:

n = First * Second

n = 6 * 6

n = 36

The pair of only B, C or F is:

Pair = \{(B,C), (B,F), (C,B),(C,F),(F,B),(F,C)\}

n(Pair) = 6

So, the probability is:

Pr = \frac{n(Pair)}{n}

Pr = \frac{6}{36}

Simplify

Pr = \frac{1}{6}

4 0
2 years ago
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