(9/18)(9/18) = 81/324. The probability that Amy takes out pink chips in both draws is 81/324.
In this example we will use the probability property P(A∩B), which means given two independent events A and B, their joint probability P(A∩B) can be expressed as the product of the individual probabilities P(A∩B) = P(A)P(B).
The total number of chips of different colors in Amy's bag is:
8 blue chips + 9 pink chips + 1 white chip = 18 color chips
Amy takes out a chip from the bag randomly without looking, she replaces the chip and then takes out another chip from the bag.
So, the probability that Amy takes out a pink chip in the first draw is:
P(A) = 9/18 The probability of takes out a pink chip is 9/18 because there are 9 pink chips in the total of 18 color chips.
Then, Amy replaces the chip an takes out another which means there are again 18 color chips divide into 8 blue chips, 9 pink chips, and 1 white chip. So, the probability of takes out a pink chip in the second draw is:
P(B) = 9/18 The probability of takes out a pink chip is 9/18 because there are 9 pink chips in the total of 18 color chips.
What is the probability that Amy takes out a pink chip in both draws?
P(A∩B) = P(A)P(B)
P(A∩B) = (9/18)(9/18) = 81/324
<h3>Answer:</h3>
64
<h3>Explanation:</h3>
6+4= 10
Then reverse the digits of 64, and you have 46
64-46= 18
Hello,
Assume x the smallest side.
y the third side
z the largest side
z=2x-4
y=10+x
x+y+z=86
==>x+(10+x)+(2x-4)=86
==>4x=86-10+4
==>x=20, y=30 and z=36
Answer:
6x^2(5x^4 +3)
Step-by-step explanation:
The greatest common factor of 18 = 3·6 and 30 = 5·6 is 6.
The greatest common factor of x^2 and x^6 is x^2.
Factoring 6x^2 from both terms, we get ...
... 18x^2 +30x^6 = 6x^2(3 +5x^4)
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<em>Comment on the question</em>
Since this answer is not among the answer choices, I suggest you ask your teacher to demonstrate how this problem is worked.
It appears as though the answers go with the problem 18x^9 +30x^6. Maybe there's a typo somewhere. For that problem, the best choice is the 2nd answer.
