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vova2212 [387]
3 years ago
10

How many triangles are there help please

Mathematics
2 answers:
mart [117]3 years ago
8 0

Answer:

35

Step-by-step explanation:

Make sure to count the right triangles the equilateral triangles as well.

zheka24 [161]3 years ago
7 0
35 And just so you know your teacher is a Satanist xd
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The equation y = 13x describes the amount of money Sarah earns, where x is the number of hours she works
enot [183]

Answer:

A) $14/hr B) Austin

Step-by-step explanation:

A)

If he earns $140 in 10 hours you can divide 140 by 10 to find out how much he makes per hour

B)

Sarah makes $13/hr which is $1 less than Austin

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3 years ago
Simplify the following inequality 3x + 12 ≥2(4x + 3) −21<br><br> Help I need the answer ASAP
Vlada [557]

Answer:

x ≤ 27/5

Step-by-step explanation:

3 0
3 years ago
A recent survey of 128 high school students indicated the following information about release times from school.
Delicious77 [7]

Answer:

A) Interval estimate for those that want to get out earlier = (35%) ± (4%) = (31%, 39%)

Interval estimate for those that want to get out later = (39%) ± (4%) = (35%, 43%)

B) The group that wants to get out of school earlier can win after all the votes are counted if their true population proportion takes on a value that is higher than the closest true population proportion (for the group that wants to get out of school later)

That is, in the (31%, 39%) and (35%, 43%) obtained in (a), a range of (35.1%, 39%) and (35%, 38.9%) show how possible that the group that wants to get out of school earlier can win after all the votes are counted.

Step-by-step explanation:

The Interval estimate for the proportion is basically an interval of range of values where the true population proportion can be found with a certain level of confidence.

Mathematically,

Interval estimate = (Sample proportion) ± (Margin of error)

Margin of Error is the width of the confidence interval about the proportion.

a) Find the interval estimates

i) for those that want to get out earlier and

ii) those that want to get out later.

i) Sample proportion of those that want to get out earlier = 35%

Margin of Error = 4%

Interval estimate for those that want to get out earlier = (35%) ± (4%) = (31%, 39%)

ii) Sample proportion of those that want to get out later = 39%

Margin of Error = 4%

Interval estimate for those that want to get out later = (39%) ± (4%) = (35%, 43%)

b) Explain how it would be possible for the group that wants to get out of school earlier to win after all the votes are counted.

Since the interval estimates represent the range of values that the true population proportion can take on for each group that prefer a particular option, the group that wants to get out of school earlier van have their proportion take on values between 31% and 39%. If their true population takes on a value that is highest (which is very possible from the interval estimate), and the group with the highest proportion in the sample, (the group that wants to get out of school later, whose true population proportion can take between 35% and 43%) has a true population proportion that is less than that of the group that wants to get out of school earlier, then, the group that wants to get out of school earlier can win after all the votes are counted.

Hope this Helps!!!

3 0
3 years ago
Which is the equation of a line with a slope of -1 and a y-intercept of -6?
nikklg [1K]

Answer:

y= -1x - 6

I really hope this helps you!

3 0
3 years ago
The distance from Wakefield to London is 180 miles. A train travels this distance in 2 hours 15 minutes. Calculate the average s
Readme [11.4K]

Answer:

v = 80 mph

Step-by-step explanation:

Given that,

The distance from Wakefield to London is 180 miles.

The train travels this distance in 2 hours 15 minutes.

We need to find the average speed of the train. The average speed of the train is equal to the total distance covered divided by the time taken.

v=\dfrac{d}{t}\\\\v=\dfrac{180\ miles}{(2+\dfrac{15}{60})\ h}\\\\v=80\ mph

So, the required average speed of the train is 80 mph.

4 0
3 years ago
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