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2 years ago

Find all solutions of the equation in the interval [0, 2π). cotθ+ √3= 0

Mathematics

1 answer:

Ilia_Sergeevich [38]2 years ago

5 0

Answer:

{5π/6, 11π/6}

Step-by-step explanation:

Since you have memorized the trig values of common angles, you know tan(π/6) = 1/√3, so cot(π/6) = √3.

The solution to this equation is ...

cot(θ) = -√3

so θ = -π/6 or, in the domain of interest, 11π/6. There is a corresponding quadrant II angle, 5π/6.

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3x + 3y =15 and x = -3y -1

saul85 [17]

Answer:

(x, y) = (8, -3)

Step-by-step explanation:

You can substitute for x in the first equation:

3(-3y -1) +3y = 15

-6y = 18 . . . . . add 3 and simplify

y = -3 . . . . . . . divide by -6

x = -3(-3) -1 = 8 . . . . find x using the second equation

The solution to this system of equations is (x, y) = (8, -3).

4 0

2 years ago

What is the best way to describe the solution for the following question 2x+3=2x-8 A) There is only one solution (x=5) B) There

Over [174]

Answer:B

Step-by-step explanation:

8 0

2 years ago

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Pavel [41]

Answer:

Assuming you mean on a number line.

5 0

2 years ago

Read 2 more answers

There are three consecutive even integers. If twice the first integer added to the second is 268,244, find all three integers.

r-ruslan [8.4K]

Answer:

89414,89416,89418

Step-by-step explanation:

Let n bet the positive integer and then 2n is an even integer because multiplying n with 2 makes it an even integer.

Now, 2n+2, 2n+4 are the next integers.

Therefore, three consecutive integers are: 2n, 2n+2, 2n+4.

It is given that twice the first integer added to the second is 268,244 that means:

$2(2n)+(2n+2)=268244$

$4n+2n+2=268244$

$6n=268242$

$n=44707$

Therefore, three consecutive integers are:

2n=89414, 2n+2=89416, 2n+4=89418

8 0

2 years ago

Calculating area of rectangle

PSYCHO15rus [73]

Answer:

$Area = 216.108cm^2$ --- You

$Area = 216.940cm^2$ --- Another student

Reason: Because there is a variation in the given dimensions

Step-by-step explanation:

Given

Your measurement

$Length = 20.70cm; Width =10.44cm$

Another students'

$Length = 20.74cm; Width =10.46cm$

Solving (a): The area

Area is calculated as:

$Area = Length * Width$

For you

$Area = 20.70cm * 10.44cm$

$Area = 216.108cm^2$

For the other student

$Area = 20.74cm * 10.46cm$

$Area = 216.940cm^2$

Solving (b): Reason for the variation in the areas

The given measurements are estimates of the dimensions of the rectangle.

Since there is a variation in the estimates, there will be some level of variation in the calculated area.

4 0

3 years ago