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Shtirlitz [24]
3 years ago
8

For the fiction f(x)=x^2+3x-28 solve the following f(x) = 0

Mathematics
1 answer:
vovikov84 [41]3 years ago
8 0

Answer:

x=4\\\\x=-7

Step-by-step explanation:

First, we need to set up the equation

x^2+3x-28=0

To solve this, we have two options: factoring or using the quadratic formula. In this case, factoring will work, so we can use that

To factor, we need to find two numbers that add together to give you 3 and multiply to give you -28

In this case, these two numbers would nee to be -4 and 7

This means that our factored equation would be:

(x-4)(x+7)=0

Now all we need to do is input the values of x that will give you 0. This means that the two solutions are

x=4\\\\x=-7

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Answer:

10.74

Step-by-step explanation:

add both digits in each column

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3 years ago
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Vinvika [58]
1)

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3)

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5 0
4 years ago
What is the solution to : 3(1/2 m - 3) =45
VladimirAG [237]

Answer:

m=36

Step-by-step explanation:

We can solve for this equation by isolating m on one side. To do this, we can "reverse" the equation.

3(\frac{1}{2}m - 3) = 45

Let's divide both sides by 3.

3(\frac{1}{2}m-3)\div3 = 45\div3\\\\\frac{1}{2}m - 3 = 15

Add 3 to both sides:

\frac{1}{2}m - 3 + 3 = 15 + 3\\\\\frac{1}{2}m = 18

Multiply both sides by two (since \frac{1}{2}\cdot2=1)

\frac{1}{2}m \cdot 2 = 18 \cdot 2\\\\m = 36

Hope this helped!

6 0
3 years ago
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A function h is defined by h(x)=−4x−72. If x decreases by 11, by how much does h(x) increase?
vladimir1956 [14]

<u>QUESTION 1</u>

The given function is


h(x)=-4x-72

If x decreases by 11, then the new value is x-11.


We need to find the value the function at x-11 which is


h(x-11)=-4(x-11)-72


This simplifies to


h(x-11)=-4x+44-72


The increment in h(x) is given by;


h(x-11)-h(x)=-4x+44-72-(-4x-72)


This simplifies to,

h(x-11)-h(x)=-4x+44-72+4x+72


This further simplifies to


h(x-11)-h(x)=44


Therefore the corresponding increment in h(x) is 44.


<u>QUESTION 2</u>

The given function is

f(x)=\frac{3}{17}x+2.


If x increases by 51, then the new value of x is x+51.


The increment in f(x) is given by

h(x+51)-h(x)=\frac{3}{17}(x+51)+2-(\frac{3}{17}x+2)


We expand the brackets to get,


h(x+51)-h(x)=\frac{3}{17}x+9+2-\frac{3}{17}x-2


We simplify further to obtain,


h(x+51)-h(x)=9


Therefore the corresponding increment in f(x) is 9.





7 0
3 years ago
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