Um, so it's a bit awkward with this question because they actually got the x value incorrect. When they added up all the values, they got 9x - 27 = 180, but it's actually 9x + 27 = 180 because -18 + 45 is positive 27. Anyways, when you solve it correctly you get x = 17, and then you substitute it into the angles. So with 5x - 18, you are saying 5(× 17) - 18 = 67. Then with the other one you do 4(× 17) + 45 = 113. You know that x is definitely 17 because 113 + 67 = 180.
FORMULA:
ANSWER:
We are given new side of square i.e, 2s + 3.
So, Area = (2s + 3)²
- (2s)² + (3)² + 2 × 2s × 3
- 4s² + 9 + 12s
Hence, The area of the new graph is a perfect square trinomial: __4__s² + __12__s +__9__.
Answer:
the probability is 0.02 (2%)
Step-by-step explanation:
defining the event S= the message is spam , then the probability is
P(S) = probability that a randomly selected message comes from account #1 * probability that the message is spam given that the message is from account #1 + probability that a randomly selected message comes from account #2 * probability that the message is spam given that the message is from account #2 + probability that a randomly selected message comes from account #3 * probability that the message is spam given that the message is from account #3 = 0.6 * 0.01 + 0.3 * 0.03 + 0.1 * 0.05 = 0.02 (2%)
thus the probability is 0.02 (2%)
Define
g = 9.8 32.2 ft/s², the acceleration due to gravity.
Refer to the diagram shown below.
The initial height at 123 feet above ground is the reference position. Therefore the ground is at a height of - 123 ft, measured upward.
Because the initial upward velocity is - 11 ft/s, the height at time t seconds is
h(t) = -11t - (1/2)gt²
or
h(t) = -11t - 16.1t²
When the ball hits the ground, h = -123.
Therefore
-11t - 16.1t² = -123
11t + 16.1t² = 123
16.1t² + 11t - 123 = 0
t² + 0.6832t - 7.64 = 0
Solve with the quadratic formula.
t = (1/2) [-0.6832 +/- √(0.4668 + 30.56) ] = 2.4435 or -3.1267 s
Reject the negative answer.
The ball strikes the ground after 2.44 seconds.
Answer: 2.44 s
These involve the rules for the power of a point. For questions 6-8, we use the theorem that the square of the length of the tangent is equal to the length of the secant multiplied by the length of its external segment.
6. 6^2 = (3)(x + 3)12 = x + 3x = 9 units
7. 4^2 = (2)(x + 2)8 = x + 2x = 6 units
8. 24^2 = (12)(x + 12)48 = x + 12x = 36 units
9. The included angle is half the difference of the larger and smaller arcs. Since the larger arc is 85 degrees, the smaller is 25 degrees, and the difference is 60. Half this difference is x = 30 degrees.
10. The angles at the intersection are vertical angles, so both equal to 65 degrees. Then the sum of the intercepted arcs must be equal to double of the vertical angle: 2 x 65 = 130 degrees. Since one is 95 degrees, the other is x = 130 - 95 = 35 degrees.