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scZoUnD [109]
2 years ago
9

Find the 64th term of the following arithmetic sequence . 12,19,26,33 ...

Mathematics
1 answer:
mr Goodwill [35]2 years ago
4 0

Answer:

sequence 12,19,26,33

1st term = 12

comman difference = 19 - (12) = 7

comman term = a + (n-1)d

a= first term

d= difference

comman term = a + (n-1)d

                       = 12 + (n-1)(7)

                       = 12 +7n-7

                       = 7n +5

1st term --> n =1 = 7.1 + 5 =  12

2nd term --> n =2 = 7.2 + 5 =  14 + 5 = 19

64st term --> n =64 = 7.64+ 5 =  448+5 = 453

Step-by-step explanation:

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Please help it would be much appreciated!!
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Answer:

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Step-by-step explanation:

4 routes to D + H

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= D  H   S

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=    2  |  3  = route 1 = 2/4  and route 2 = 3/6

= 1/2 route 1 and 1/2 route 2

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Answer b)  = 1- (1/2 x 1/2) = 1- 0.25 = 3/4 = 0.75 probability

Answer c)  = 1/2 x 1/2 = 0.25 = 1/4 = 0.25 probability  

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2 years ago
Two positive integers have a product of 200.
sattari [20]

Since 200 is a constant, of x, move 200 out of the integral. 200x+c. Constant is a fixed value that does not change.

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2 years ago
Find the distance between points (2,-9) and (-1,4) using the distance formula
defon
If you use the square root and put it in (-1-2)^2+(4--9)^2 it will equal = 13.34166406
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How many arrangements of 3 types of flowers are there if there are 6 types to choose from?,
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