<u>Answer:</u>
1) Distance traveled by bird = 403 meter
2)Average speed = 1.66 km /hour
3) Zcceleration = 2
<u>Explanation:</u>
1) Distance traveled = Speed * Time taken = 31 * 13 = 403 meter.
2) Average speed = Total distance covered / Time taken for that distance to cover.
Total distance covered = 2+0.5+2.5 = 5 km
Time taken = 3 hours
Average speed = 5/3 = 1.66 km /hour
3) Acceleration is defined as the rate of change of velocity, so acceleration a = change in velocity/time.
Change in velocity = 14 - 6 = 8 m/s
Time = 4 seconds
So acceleration = 8 / 4 = 2
The wave nature of light, due to the experiment having bright and dark bands corresponding to places where you have constructive and destructive interference.
Answer:
Explanation:
From the exercise we know that the force on the plane is 7934N upward at an angle of 54.2º.
If analyze the forces in the vertical direction, the acceleration is zero because the plane is moving with constant velocity
∑
So, the <u><em>weight of the plane</em></u> is 6435N
Answer:
Speed is the time rate at which an object is moving along a path while velocity is the rate and direction of an object's movement
Answer:
The magnitude of the net current = 18 A.
Direction of the net current is along the negative z axis.
Explanation:
<u><em></em></u>
<u><em>Given:</em></u>
- Number of electrons flow through the given cross section,
- Number of electrons flow through the given cross section,
- Time interval for which the electrons and protons flow,
The current through a cross section is defined as the amount of charge passing through that cross section in unit time.
We know,
Charge on an electron,
Charge on a proton,
Therefore,
The amount of charge flowing due to electrons is given by
The amount of charge flowing due to protons is given by
The current flowing through the cross section because of the electrons is given as:
The negative sign shows that the current is due to the flow of negative charge, and the direction of current is always opposite to that of flow of negative charge i.e., electrons.
Thus, the direction of this current is along the negative z direction.
The magnitude of this current = 12 A.
The current flowing through the cross section because of the protons is given as:
The direction of this current is same as that of electrons,
The directions of the currents due to both, the electrons and the protons are along the negative z direction, therefore the magnitude of the net current is given as: