Question

On takeoff, the combined action of the engines and wings of an airplane exerts a(n) 7934 N force on the plane, directed upward at an angle of 54.2 ◦ above the horizontal. The plane rises with constant velocity in the vertical direction while continuing to accelerate in the horizontal direction. The acceleration of gravity is 9.8 m/s 2 . What is the weight of the plane? Answer in units of N.

Answer 1

Answer:

$W=6435N$

Explanation:

From the exercise we know that the force on the plane is 7934N upward at an angle of 54.2º.

If analyze the forces in the vertical direction, the acceleration is zero because the plane is moving with constant velocity

∑$F_{y}=7934sin(54.2)-W=0$

$W=7934sin(54.2)N=6435N$

So, the weight of the plane is 6435N