Answer:
3 seconds
Explanation:
To solve this problem, we have to find the acceleration of the car.
Acceleration is given as:
a = (v - u) / t
Where v = final velocity
u = initial velocity
t = time taken.
From the question,
u = 0 m/s
v = 31 mph = 13.86 m/s
t = 1.5 seconds
Acceleration, a, will be:
a (13.86 - 0) / 1.5
a = 13.86 / 1.5
a = 9.24 m/s²
We are told that this kind of car operates with constant force. This means it operates with constant acceleration (since force and acceleration are directly proportional)
Therefore, when the final velocity of the car is 62 mph (27.72 m/s), time taken is:
a = (v - u) / t
=> t = (v - u) / a
t = (27.72 - 0) / 9.24
t = 3 seconds
It will take the car 5 seconds to go from zero to 62 mph.
Answer:
-194 m/s
Explanation:
We are taking as a reference point the position of the sun
In this case,
The spacecraft is moving with a velocity of +126 m/s
The asteroid is moving past in a backwards direction at 68 m/s relative to the spacecraft.
Speed of the asteroid - speed of the spacecraft = 68m/s
Speed of the asteroid = 68 m/s + 126 m/s
Speed of the asteroid = 194 m/s (backwards)
Beacuse the asteroid is moving in the opposite direction of the spacecraft
The asteroid has a velocity of -194m/s relative to the position of the Sun
Answer:
3.3 × 10-10 joules
Explanation:
For the law of conservation of energy, the loss in electrical potential energy of the charge must be equal to the gain in kinetic energy of the particle:
the kinetic energy of the charge at point A is zero: , so we can immediately find the kinetic energy of the charge at point B:
A.helium has no valency
B.lithium has 1
C.nitrogen has either 5 or 3 because it bonds outer orbital
D.magnesium has 2
To answer that question, we don't care what the highest and lowest
levels of the wave are, or how far apart they are. We only need to be
able to identify the highest point on the wave, and keep track of how
often those pass by us.
You said it takes 4 seconds for a complete wave to pass by.
Through the sheer power of intellect, I'm able to take that information
and calculate that 1/4 of the wave passes by in 1 second.
There's your frequency . . . 1/4 per second, or 0.25 Hz.