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2 years ago

Simplify

Mathematics

1 answer:

Alexandra [31]2 years ago

5 0

Answer:

Step-by-step explanation:

u just have to think about it

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Q2.<br>a) Is the equality √a^4 = a valid for all values of a? Explain.<br>

allochka39001 [22]

Answer:

The equality is only true for $a = 0\ and\ 1$ , not for all values

Step-by-step explanation:

Given

$(\sqrt a)^4 = a$

Required

Determine if it is valid

$(\sqrt a)^4 = a$

Evaluate the exponent

$(a^\frac{1}{2})^4 = a$

$a^\frac{1*4}{2} = a$

$a^2 = a$

Rewrite as:

$a^2 - a = 0$

Factorize

$a(a- 1) = 0$

$a =0\ or\ a - 1 = 0$

$a =0\ or\ a = 1$

<em>The equality is only true for </em> $a = 0\ and\ 1$ <em>, not for all values</em>

7 0

2 years ago

For which equation is w= 4 not the solution?

ale4655 [162]

Answer:

w - 2 = 4

Step-by-step explanation:

4-2 is not equal to 4. therefore, w does not equal 4.

3 0

3 years ago

Read 2 more answers

The volume of a cylinder whose base,area is 500sq.cm and height is 14 cm is cu.cm

Allisa [31]

<h3> $\huge\bigstar\:$ $\Huge\tt\underline\blue{ANSWER}$ </h3><h3 /><h3 /><h3>The area is 7000.</h3>

$\huge\bigstar\:$ $\Huge\tt\underline\red{EXPLAINATION}$

The base of the cylinder = 5000 sq.cm

Height = 14cm

The volume of the cylinder = 5000× 14 = 7000

<h3>HOPE IT HELPS YOU :)</h3>

6 0

3 years ago

Please help me complete this !! 12points

Svet_ta [14]

Answer:

x1=1

x2=3

y1=5

y2=1

midpoint= (x1+x2/2, y1+y2/2)=(1+3/2,5+1/2)=(2,3)

x1=2

x2=4

y1=4

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(2+4/2,4+6/2)=(3,5)

x1= -2

x2=4

y1=4

y2= -6

midpoint= (x1+x2/2, y1+y2/2)=(-2+4/2,4-6/2)=(1,-1)

x1=0

x2=0

y1=3

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(0/2,3+5/2)=(0,4)

x1= -2

x2=2

y1= -6

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(-2+2/2,-6+6/2)=(0,0)

x1=1

x2=4

y1=4

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(1+4/2,4+5/2)=(5/2,9/2)

x1=-3

x2=-4

y1=5

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(-3-4/2,5+5/2)=(-7/2,5)

x1=5

x2= -4

y1=2

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(5-4/2,2+6/2)=(1/2,4)

3 0

2 years ago

The figure shown below is a rhombus. Give the angle value (numerical, not the letters.

Rzqust [24]

Answer:

90 deg

Step-by-step explanation:

Recall that for a rhombus, the diagonals always intersect at right angles.

Hence angle PXM is 90 deg

6 0

3 years ago

Read 2 more answers