Question

PLZ HELP WILL GIVE BRAINLIEST WORTH 10 PTS THX!!

Answer 1

Answer:

  64/49

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)^c = a^(bc)

  (a^b)(a^c) = a^(b+c)

  a^-b = 1/a^b

  a^0 = 1

_____

Using these rules, we can simplify the given expression to ...

  $\left(\dfrac{8\cdot 4\cdot 2}{8\cdot 7}\right)^2\times\left(\dfrac{8^0}{7^{-3}}\right)^3\times 7^{-9}\\\\=\dfrac{8^2}{7^2}\times(8^{0\cdot 3}\cdot 7^{3\cdot 3})\times 7^{-9}\\\\=\dfrac{64}{49}\times(8^07^{9-9})=\boxed{\dfrac{64}{49}}$

Answer 2

Answer:

Answer 64/49 Decimal 1.30612

Step-by-step explanation:

( 1 / 7^-3 ) ^3 = 7^9

7^9 * 1 / 7^9 * 8^2 / 7^2

8^2 * 1 * 7^9 / 7^2 * 7^9

8^2/7^2

64/7^2

Good luck