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Stolb23 [73]
3 years ago
8

Circumference of earth is 25,000 miles. Find it's diameter

Mathematics
1 answer:
NISA [10]3 years ago
7 0
C=/pi (d) that's the formula to find circumference
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On a coordinate plane, the orange K is shifted to form the purple K, reflected across the x-axis to form the green k, and rotate
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Answer:

the green kin quadrant IV

Step-by-step explanation:

i took the quiz and got it right

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A planet has a circular orbit around a star. It is a distance of 81,000,000 km from the centre of the star. It orbits at an aver
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81,000,000 \text{ km} \left(\frac{1 \text{ h}}{46,000 \text{ km}} \right) =\frac{40500}{23} \text{ h} \\ \\ \frac{40500}{23} \text{ h} \left(\frac{1 \text{ days}}{24 \text{ hours}} \right) \approx \boxed{73 \text{ days}}

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Pls open first to answer correctly get brainlist
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5 0
3 years ago
Read 2 more answers
a cell phone plan offers 250 minutes each month for 15.00 dollars per month. what is the cost per minute when a person uses all
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4 0
3 years ago
A skier has decided that on each trip down a slope, she will do 3 more jumps than before. On her first trip she did 5 jumps. Der
taurus [48]
Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.

Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.

Let us try it below:

Sigma notation 1:

  10
<span>   Σ (2i + 3)
</span>i = 3

@ i = 3

2(3) + 3
12

The first sigma notation does not have the same result, so we move on to the next.

  10
<span>   Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.

When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)

Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.


3 0
3 years ago
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