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enot [183]
3 years ago
9

Help me please !!!!!!!

Mathematics
2 answers:
wlad13 [49]3 years ago
8 0
Answer: third option:    4( \sqrt[3]{16})^{2x

Explanation:

4( \sqrt[3]{16})^{2x}=4( \sqrt[3]{16^2})^x  =4( \sqrt[3]{4^4} )^x=4(4 \sqrt[3]{4})^x


I used 16^2 = 4^4

Later, I used 4^4 = 4^3 . 4
lana66690 [7]3 years ago
6 0
None of the given answers are correct. We can check that fairly quickly:
4\sqrt[3]{4}=\sqrt[3]{4^4}=\sqrt[3]{4}=\sqrt[3]{256}
Now let's do the same thing for given answers:
a) 2\sqrt[3]{16}=\sqrt[3]{8\cdot 16}=\sqrt[3]{128}\\
b) 2\sqrt[3]{64}=\sqrt[3]{8\cdot 64}=\sqrt[3]{512}\\

I don't have to continute, it's pretty obvious that answers C and D are wrong (notice we multiply by 4 and on top of that we square the third root).
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Answer:

d is 18, a is 11, c is 9 and b is 12

Step-by-step explanation:

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3 years ago
2 number cubes are rolled. (a) List the sample space. (b)What is the probability, as a simplified fraction, that the sum of the
melomori [17]

Solution:

When two number cubes  are rolled,

Sample space= Total Possible outcome {11,22,33,44,55,66,12,21,13,31,14,41,15,51,16,61,23,32,24,42,25,52,26,62,34,43,35,53,36,63,45,54,46,64,56,65}=36

Probability of an event = \frac{\text{Total favorable outcome}}{\text{Total possible outcome}}

Sum of 4 is obtained when ={13,31,22}=3

Probability of getting 4 when 2 number cubes are rolled= \frac{3}{36}=\frac{1}{12}

Sum of the numbers is greater than 9= 10, 11,12={55,64,46,56,65,66}=6

Probability of getting(Sum of the numbers is greater than 9)=\frac{6}{36}=\frac{1}{6}



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harkovskaia [24]
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Answer:

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Step-by-step explanation:

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