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enot [183]
3 years ago
9

Help me please !!!!!!!

Mathematics
2 answers:
wlad13 [49]3 years ago
8 0
Answer: third option:    4( \sqrt[3]{16})^{2x

Explanation:

4( \sqrt[3]{16})^{2x}=4( \sqrt[3]{16^2})^x  =4( \sqrt[3]{4^4} )^x=4(4 \sqrt[3]{4})^x


I used 16^2 = 4^4

Later, I used 4^4 = 4^3 . 4
lana66690 [7]3 years ago
6 0
None of the given answers are correct. We can check that fairly quickly:
4\sqrt[3]{4}=\sqrt[3]{4^4}=\sqrt[3]{4}=\sqrt[3]{256}
Now let's do the same thing for given answers:
a) 2\sqrt[3]{16}=\sqrt[3]{8\cdot 16}=\sqrt[3]{128}\\
b) 2\sqrt[3]{64}=\sqrt[3]{8\cdot 64}=\sqrt[3]{512}\\

I don't have to continute, it's pretty obvious that answers C and D are wrong (notice we multiply by 4 and on top of that we square the third root).
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