That is the slope at f(1)
one way is to just take the derivitive
f'(x)=2x+(1/x)
for ti-89, do calc then derivitive then input "x^2+ln(x),x)" and click enter to get the derivitive
you would get f'(x)=2x+(1/x)
an easier way would be to have
click calc then differntiate then type x^2+ln(x),x)|x=1 then click enter
you get f'(1)=3
answer is 3
Answer: x=4, y=-2
Step-by-step explanation: 4x+y=14, x-2y=8
4x+y-y=14-y
4x/4=14/4-y/4
x=14-y/4-(2y)(4)/4
4(14-9y)/4=(8)(4)
14-9y-14=32-14
-9y/-9=18/-9
y=-2
(14)-(-2)/4
14+2/4
16/4
4
x=4
x=4, y=-2
Answer:
C
Step-by-step explanation:
The first equation has a y-intercept of -3. Only one line does.
The second equation has a y-intercept of +1. Only one line does.
The point of intersection of those two lines is the point labeled C. That has coordinates that satisfy both equations. (The point is on both lines.)
Answer:
<span>−<span>45</span></span>
<span><span>
</span></span>
Explanation:
Since <span><span>tan<span>(θ)</span></span>=<span>34</span>>0</span> and <span><span>sin<span>(θ)</span></span><0</span>, θ is in quadrant 3 (since <span><span>tan<span>(θ)</span></span>>0</span> iff θ is in quadrant 1 or 3 and <span><span>sin<span>(θ)</span></span><0</span> iff θ is in quadrant 3 or 4).
<span>cos<span>(θ)</span></span> must then be negative.
