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Lyrx [107]
3 years ago
5

Sum and Product of zeroes of the quadratic polynomial 16s² - 16s + 4 respectively is:Sum and Product of zeroes of the quadratic

polynomial 16s² - 16s + 4 respectively is:​
Mathematics
1 answer:
andrew-mc [135]3 years ago
4 0

Answer:

The sum and product of zeroes are 1 and 1/4, respectively.

Step-by-step explanation:

To determine the zeroes of the quadratic polynomial, let equalize the polynomial to zero and solve in consequence:

16\cdot s^{2}-16\cdot s + 4 = 0

By the General Quadratic Formula:

s_{1,2} = \frac{16\pm \sqrt{(-16)^{2}-4\cdot (16)\cdot (4)}}{2\cdot (16)}

s_{1,2} = \frac{1}{2}

Which means that zeroes are s_{1}=s_{2}=\frac{1}{2}.

The sum and product of zeroes are, respectively:

s_{1}+s_{2} =\frac{1}{2}+\frac{1}{2}

s_{1}+s_{2} = 1

s_{1}\cdot s_{2} = \left(\frac{1}{2} \right)^{2}

s_{1}\cdot s_{2} = \frac{1}{4}

The sum and product of zeroes are 1 and 1/4, respectively.

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