Question

Sum and Product of zeroes of the quadratic polynomial 16s² - 16s + 4 respectively is:Sum and Product of zeroes of the quadratic polynomial 16s² - 16s + 4 respectively is:​

Answer 1

Answer:

The sum and product of zeroes are 1 and 1/4, respectively.

Step-by-step explanation:

To determine the zeroes of the quadratic polynomial, let equalize the polynomial to zero and solve in consequence:

$16\cdot s^{2}-16\cdot s + 4 = 0$

By the General Quadratic Formula:

$s_{1,2} = \frac{16\pm \sqrt{(-16)^{2}-4\cdot (16)\cdot (4)}}{2\cdot (16)}$

$s_{1,2} = \frac{1}{2}$

Which means that zeroes are $s_{1}=s_{2}=\frac{1}{2}$.

The sum and product of zeroes are, respectively:

$s_{1}+s_{2} =\frac{1}{2}+\frac{1}{2}$

$s_{1}+s_{2} = 1$

$s_{1}\cdot s_{2} = \left(\frac{1}{2} \right)^{2}$

$s_{1}\cdot s_{2} = \frac{1}{4}$

The sum and product of zeroes are 1 and 1/4, respectively.