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belka [17]
3 years ago
11

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!! I CANNOT RETAKE THIS!! Simplify.

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
8 0

Answer:  \frac{2x(5x + 1)}{4x - 1}

<u>Step-by-step explanation:</u>

\frac{4x^{3}-12x^{2}}{4x^{2}+7x - 2} ÷ \frac{2x^{2}-6x}{5x^{2}+11x + 2}

= \frac{4x^{2}(x - 3)}{(4x - 1)(x + 2)} ÷ \frac{2x(x - 3)}{(5x + 1)(x + 2)}

= \frac{4x^{2}(x - 3)}{(4x - 1)(x + 2)} x \frac{(5x + 1)(x + 2)}{2x(x - 3)}

= \frac{2x(5x + 1)}{4x - 1}

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There is a "trick" to determine divisibility by 3: if the sum of the digits is divisible by 3, the number is divisible by 3.

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Only even numbers are divisible by 2.

If a 3-digit number is divisible by 11, the middle digit will be the sum of the first and last digits.   (That is not the case for 315)  But 385 is divisible by 11, also 495, 253, and many others you can try for fun.

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