Answer:
(6-√21, 6+√21)
Step-by-step explanation:
x^2 - 12x = -15
(x - 6)^2 - 36 = -15
(x - 6)^2 = 21
x - 6 = ± √21
x = 6 ± √21
Let's solve your equation step-by-step.
4(2x+8)=10x+2−2x+30
Step 1: Simplify both sides of the equation.
4(2x+8)=10x+2−2x+30
(4)(2x)+(4)(8)=10x+2+−2x+30(Distribute)
8x+32=10x+2+−2x+30
8x+32=(10x+−2x)+(2+30)(Combine Like Terms)
8x+32=8x+32
8x+32=8x+32
Step 2: Subtract 8x from both sides.
8x+32−8x=8x+32−8x
32=32
Step 3: Subtract 32 from both sides.
32−32=32−32
0=0
Answer:
All real numbers are solutions.
<span>−8x+5−2x−4+5x
= -5x + 1
so when x = 2 then
</span>-5x + 1
= -5(2) + 1
= -9
hope it helps
Answer: 4.5 miles
Explanation:
When you draw the situation you find two triangles.
1) Triangle to the east of the helicopter
a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°
b) hypotensue = distance between the high school and the helicopter
c) opposite-leg to angle 20° = heigth of the helicopter
d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x
2) triangle to the west of the helicopter
a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°
b) distance between the helicopter and the elementary school = hypotenuse
c) opposite-leg to angle 62° = height of the helicopter
d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x
3) tangent ratios
a) triangle with the helicpoter and the high school
tan 20° = Height / x ⇒ height = x tan 20°
b) triangle with the helicopter and the elementary school
tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°
c) equal the height from both triangles:
x tan 20° = (5 - x) tan 62°
x tan 20° = 5 tan 62° - x tan 62°
x tan 20° + x tan 62° = 5 tan 62°
x (tan 20° + tan 62°) = 5 tan 62°
⇒ x = 5 tant 62° / ( tan 20° + tan 62°)
⇒ x = 4,19 miles
=> height = x tan 20° = 4,19 tan 20° = 1,525 miles
4) Calculate the hypotenuse of this triangle:
hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²
hipotenuse = 4.46 miles
Rounded to the nearest tenth = 4.5 miles
That is the distance between the helicopter and the high school.
Answer:
A D F
Step-by-step explanation:
i think
pls mark brainliest
