I need help please.

Alejandro uses the steps below to convert StartFraction 5 over 8 EndFraction to a percent. Five-eighths right arrow 8. 0 divided

adoni [48]

Alejandro makes an error in the first steps he divides 8 by 5 which is incorrect he has to divide 5 by 8, and in the second step, he does not multiply the term by 100 and it can be determined by using fraction or percentage.

<h2>Given that,</h2>

Alejandro uses the steps below to convert 5/8 to a percent.

8 divided by 5 = 1.6.,

1.6 = 160 percent

<h3>We have to determine,</h3>

Which best explains Alejandro's error?

<h3>According to the question,</h3>

Alejandro uses the steps below to convert 5/8 to a percent.

8 divided by 5 = 1.6.,

1.6 = 160 percent

The division was computed incorrectly.

The division was completed in the incorrect order. The decimal was moved to the right too many times.

The decimal was moved to the right instead of the left.

Alejandro uses the steps below to convert 5/8 to a percent.

To convert 5/8 into percentages following all the steps given below.

Step1; Firstly 5 is divided by 8,

$= \dfrac{5}{8} \\\\ = 0.625$

Step2; To convert 0.625 into percentage multiplied by 100,

$\rm = 0.625 \times 100\\\\= 62.5 \ percent$

Hence, Alejandro makes an error in the first steps he divides 8 by 5 which is incorrect he has to divide 5 by 8, and in the second step, he does not multiply the term by 100.

For more details about the Equation refer to the link given below.

brainly.com/question/18187260

7 0

2 years ago

What is the root 81/289<br><br> 1/2<br><br> 9/17<br><br> -1/2<br><br> -9/17

Usimov [2.4K]

Divide 81/289 and see the decimals value
then check each answer choice and the one with the same decimals value as your question is your answer

6 0

3 years ago

Write the percent as a decimal.<br> 47.63%.

Novay_Z [31]

0.4763 is the answer I got

8 0

3 years ago

Read 2 more answers

The true average diameter of ball bearings of a certain type is supposed to be 0.05 in. A one-sample t-test will be carried out

satela [25.4K]

Answer:

a) H0: $\mu \leq \mu_o$

H1: $\mu > \mu_o$

n = 13 represent the sample size

$t = 1.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 13-1=12$

We can calculathe the p value with this formula:

$p_v = P(t_{12} >1.6) = 0.068$

Since $p_v >\alpha$ we fail to reject the null hypothesis on this case at 5% of significance.

b) H0: $\mu \geq \mu_o$

H1: $\mu < \mu_o$

n = 13 represent the sample size

$t = -1.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 13-1=12$

We can calculathe the p value with this formula:

$p_v = P(t_{12}$

Since $p_v >\alpha$ we fail to reject the null hypothesis on this case at 5% of significance.

c) H0: $\mu \geq \mu_o$

H1: $\mu < \mu_o$

n = 25 represent the sample size

$t = -2.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 25-1=24$

We can calculathe the p value with this formula:

$p_v = P(t_{24}$

Since $p_v$ we can reject the null hypothesis on this case at 1% of significance.

Step-by-step explanation:

Part a

For this case we assume that we are testing the following system of hypothesis

H0: $\mu \leq \mu_o$

H1: $\mu > \mu_o$

n = 13 represent the sample size

$t = 1.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 13-1=12$

We can calculathe the p value with this formula:

$p_v = P(t_{12} >1.6) = 0.068$

Since $p_v >\alpha$ we fail to reject the null hypothesis on this case at 5% of significance.

Part b

For this case we assume that we are testing the following system of hypothesis

H0: $\mu \geq \mu_o$

H1: $\mu < \mu_o$

n = 13 represent the sample size

$t = -1.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 13-1=12$

We can calculathe the p value with this formula:

$p_v = P(t_{12}$

Since $p_v >\alpha$ we fail to reject the null hypothesis on this case at 5% of significance.

Part c

For this case we assume that we are testing the following system of hypothesis

H0: $\mu \geq \mu_o$

H1: $\mu < \mu_o$

n = 25 represent the sample size

$t = -2.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 25-1=24$

We can calculathe the p value with this formula:

$p_v = P(t_{24}$

Since $p_v$ we can reject the null hypothesis on this case at 1% of significance.

8 0

3 years ago

What does this mean? I do not understand

aleksley [76]

Answer:

so basically it has given the problem so what you have to do is in the side that says given write what they did in the problem beside it. Hope i helped <3

Step-by-step explanation:

8 0

4 years ago

I need help please. ​

I need help please.