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Komok [63]
3 years ago
9

Solve the linear inequality −7x+2<23

Mathematics
1 answer:
AnnZ [28]3 years ago
3 0
First we have to move the two over to get the x alone

-7x+2∠23
     -2  -2

-7x ∠21

then divide by -7 to get the answer

-3∠x

thats your final answer
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When writing a repeating decimal as a fraction does the number of repeating digits you use matter
umka21 [38]
Yes, it matters, if it is recurring or simply just irrational <span />
4 0
3 years ago
Marlin davies buys a truck for 28,000. In three years , the car depreciates 48% in value how much is the car worth in three year
Scrat [10]
$28,000
 X  48%
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$13,440

The truck would be worth $13,440 by the end of the 3 year time span. Hope this helps!

5 0
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Determine the domain and range of the graphed function
insens350 [35]

Answer:

B

Step-by-step explanation:

5 0
3 years ago
Find two consecutive integers such that the smaller integer is six more than twice the larger integer
ZanzabumX [31]
Let the integers be x and x+1.

x = 6 + 2(x + 1)

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x = -8

Hence, the integers are -8 and -7.
8 0
3 years ago
Find the center and radius of the sphere whose equation is given by x2+y2+z2−2x−4y+8z+17=0x2+y2+z2−2x−4y+8z+17=0.
Vedmedyk [2.9K]
We know that
the equation of a sphere is
(x-h)²+(y-k)²+(z-l)²=r²
where (h,k,l) is the center and r is the radius

we have
x²+y²+z²<span>−2x−4y+8z+17=0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x²+2x)+(y²-4y)+(z²+8z)=-17
<span>Complete the square. Remember to balance the equation by adding the same constants to each side
</span>(x²+2x+1)+(y²-4y+4)+(z²+8z+16)=-17+1+4+16
(x²+2x+1)+(y²-4y+4)+(z²+8z+16)=4

Rewrite as perfect squares

(x+1)²+(y-2²)+(z+4)²=4

(x+1)²+(y-2²)+(z+4)²=2²

the center is the point (-1,2,-4) and the radius is 2 units




4 0
3 years ago
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