-3/4 + p = 1/2
p = 1/2 + 3/4
p = 2/4 + 3/4
p = 5/4 or 1 1/4
Answer:
X = 40
Step-by-step explanation:
Answer:
![26.13ft^2](https://tex.z-dn.net/?f=26.13ft%5E2)
Step-by-step explanation:
Step 1 - As both triangles have lengths the same size, they both add together to equal a rectangle. Therefore:
4 x 3 = 12
Which is the area of the triangles.
Step 2 - Calculating the area of a circle uses the formula:
![\pi r^2](https://tex.z-dn.net/?f=%5Cpi%20r%5E2)
Where r is the radius of the circle.
Plug the known variables in:
![\pi \cdot 3^2\\\pi \cdot 9\\3.14 \cdot 9 = 28.26\\](https://tex.z-dn.net/?f=%5Cpi%20%5Ccdot%203%5E2%5C%5C%5Cpi%20%5Ccdot%209%5C%5C3.14%20%5Ccdot%209%20%3D%2028.26%5C%5C)
However, this is the area of a full circle. The figure is only half a circle so we must divide this by two:
28.26 ÷ 2 = 14.13
Now, add the area of the semi-circle to the area of the triangles:
14.13 + 12 = 26.13
Therefore, the area of the figure is
.
Hope this helps!
Answer:
<h2>In the attachment</h2>
Step-by-step explanation:
![y-2x>-8\qquad\text{add}\ 2x\ \text{to both sides}\\\\y>2x-8\\-------------------------\\\\-\ dotted\ line\\\leq,\ \geq-\ solid\ line\\,\ \geq-\ shading\ above\ the\ line\\-------------------------\\\\y=2x-8-\text{It's a linear function.}\\\text{We only need two points to draw a graph.}\\\text{Choice two arbitrary values of x, substitute to the equation,}\\\text{and calculate the values of y}.\\\\for\ x=4\to y=2(4)-8=8-8=0\to A(4,\ 0)\\for\ x=0\to y=2(0)-8=0-8=-8\to B(0,\ -8)](https://tex.z-dn.net/?f=y-2x%3E-8%5Cqquad%5Ctext%7Badd%7D%5C%202x%5C%20%5Ctext%7Bto%20both%20sides%7D%5C%5C%5C%5Cy%3E2x-8%5C%5C-------------------------%5C%5C%5C%5C%3C%2C%5C%20%3E-%5C%20dotted%5C%20line%5C%5C%5Cleq%2C%5C%20%5Cgeq-%5C%20solid%5C%20line%5C%5C%3C%2C%5C%20%5Cleq-%5C%20%5C%20shading%5C%20below%5C%20the%5C%20line%5C%5C%3E%2C%5C%20%5Cgeq-%5C%20shading%5C%20above%5C%20the%5C%20line%5C%5C-------------------------%5C%5C%5C%5Cy%3D2x-8-%5Ctext%7BIt%27s%20a%20linear%20function.%7D%5C%5C%5Ctext%7BWe%20only%20need%20two%20points%20to%20draw%20a%20graph.%7D%5C%5C%5Ctext%7BChoice%20two%20arbitrary%20values%20of%20x%2C%20substitute%20to%20the%20equation%2C%7D%5C%5C%5Ctext%7Band%20calculate%20the%20values%20of%20y%7D.%5C%5C%5C%5Cfor%5C%20x%3D4%5Cto%20y%3D2%284%29-8%3D8-8%3D0%5Cto%20A%284%2C%5C%200%29%5C%5Cfor%5C%20x%3D0%5Cto%20y%3D2%280%29-8%3D0-8%3D-8%5Cto%20B%280%2C%5C%20-8%29)