Because the polynomial has degree 2, we can assume that there are 2 solutions (roots), whether real or imaginary.
You can subtract 60 in order to put this in standard form
48x^2+44x-60 = 0
From there, just put a,b, and c into the quadratic formula and you're good to solve for your answers.
(-b+-sqrt(b^2-4ac))/2a
(-44+-sqrt(44^2-4(48)(-60)))/2(48)
Then solve.
There is probably a better way, but this should give you the two roots/solutions.
Step-by-step explanation:
hope this helped you :)) !!
Answer:
a. is 1 and b is 2 and c is 3 I did it in algebra pay attention in class
Answer:
y = 4x - 2
Step-by-step explanation:
Answer:
14.2cm
Step-by-step explanation:
Complete question:
<em>In circle O, the length of radius OL is 6 cm and the length of arc LM is 6.3 cm. The measure of angle MON is 75°. </em>
<em>Rounded to the nearest tenth of a centimeter, what is the length of arc LMN? </em>
<em></em>
Find the diagram attached
arc LN= arc LM + arc MN
First we need to get the arc MN
length of an arc = theta/360 * 2πr
length of arc MN = 75/360 * 2(3.14)(6)
length of arc MN = 0.20833*37.68
length of arc MN = 7.85
Hence;
arc LN = 6.3 + 7.85
arc LN = 14.15cm
Hence the length of arc LN is 14.2cm