Question

Use the parabola tool to graph the quadratic function f(x)=2x2+32x+126 . Graph the parabola by first plotting its vertex and then plotting a second point on the parabola

Answer 1

$f(x)=2x^2+32x+126$

Graph the parabola by first plotting its vertex and then plotting a second point on the parabola.

To find x coordinate of vertex we use formula $x =\frac{-b}{2a}$

From the given equation , a= 2 , b= 32, c= 126

Plug in all the values

$x =\frac{-32}{2*2}$ = -8

Now plug in 8 for x in f(x)

$f(x)=2x^2+32x+126$

$f(-8)=2(-8)^2+32(-8)+126$ = -2

So vertex is (-8,-2)

Now we make a table to get some other points for graphing. We assume x value before and after vertex. Plug in -9 and -7 for x in f(x) and find out y .

$f(x)=2x^2+32x+126$

$f(-9)=2(-9)^2+32(-9)+126$ = 0

$f(-7)=2(-7)^2+32(-7)+126$ = 0

x ------> y

-9 ------> 0

-8 -------> -2

-7 --------> 0

Now we graph all the points.

Graph is attached below.

Answer 2

Here are a bunch of CORRECT answers, your answer is somewhere in there. For the first CORRECT answer the second point is -5,-9. Don't make the same mistake I did on question 3.