Answer:
60 mph
Step-by-step explanation:
Given;
Total distance covered d = 440 miles
Average speed in the first 4 hours v1 = 50 mph
Total time taken for the whole trip t = 8:00 to 4:00pm
t = 16:00-8:00 = 8 hours
Firstly we need to calculate the distance covered during the first 4 hours;
d1 = average speed × time = v1 × t1
t1 = 4
d1 = 50 × 4 = 200 miles
Then we need to calculate the distance covered in the second period of the journey;
d = d1 + d2
d2 = d - d1
Substituting the values;
d2 = 440 - 200
d2 = 240 miles
The time taken for the second period of travel t2;
t2 = t -t1 = 8-4
t2 = 4 hours
Average speed = distance travelled ÷ time taken
The average speed for the second part of the trip v2 is;
v2 = d2 ÷ t2
Substituting t2 and d2;
v2 = 240 miles ÷ 4 hours
v2 = 60 mph
The average speed during the second part of the trip is 60 mph
Hi there!
Something really good to remember about trigonometry is SOHCAHTOA. I won’t dive into too much detail about it, but you should google it for future assignments.
Anyways,
tan50°=14/AB
ABtan50°=14
AB=14/tan50°
AB=11.75
cos50°=14/AC
ACcos50°=14
AC=14/cos50°
AC=21.78
For the measure of angle C you can use a theorem called the third angle theorem. In every single possible triangle, the sum of all three angles adds up to 180°. You can set up an equation like so...
angleC=180-(90+50)
angleC=180-140
angleC=40°
Answer:
The diagonal side length shouldn't be 14. Or one of the side lengths shouldn't be what it is.
Step-by-step explanation:
It’s a pentagon (5 sides) . (n-2) x 180°. if you put it into the formula and do the reverse. 540 / 180 = 3
, 3+2 = 5
Answer:
The answer would be 118.4%
Step-by-step explanation:
