(2x^2)^-4 how to solve this problem

1. There are two differnt maps of Ohio. The scale on the first map is 1 cm to 10 km. The distance from Cleveland to Cincinnati i

xeze [42]

Answer:

1. 0.8 cm

2. 1.6 cm

Step-by-step explanation:

1.

The scale for 2nd map is 1 cm to 50 km, that means "1 cm on map" is "50 km in real life".

We already know distance from Cleveland to Cincinnati is 40 km, which is less than 50, so we know the distance on map would be less than 1 cm.

So we set up ratio and figure out (let x be distance on map from Cleveland to Cincinnati):

$\frac{1}{50}=\frac{x}{40}\\50x=40\\x=\frac{40}{50}\\x=0.8$

Hene, 0.8 centimeters would be the distance in 2nd map

2.

A scale of 1:50 means 1 cm equal 50 cm

So, 0.8m would be

0.8 * 100 = 80 cm

Hence, 80 cm would be represented by 80/50 on the map, that is:

$\frac{80}{50}=1.6$

That is 1.6 centimeters

7 0

2 years ago

1. Each side of a square barn is 9 meters long.

oksian1 [2.3K]

Answer:

The area and the perimeter of the square barn which has each side 9 meters long is 81 m² and 36 m.

Step-by-step explanation:

7 0

1 year ago

Read 2 more answers

Plz help!! I can't find the answer, the one I put in is wrong.

hichkok12 [17]

Answer:

3:23 to 3:24

Step-by-step explanation:

explantion between these to points the slope of the graph hits 3:24 hard

8 0

3 years ago

Read 2 more answers

What is the measure of _RVE?

marysya [2.9K]

Answer:

D. 45

Step-by-step explanation:

All angles have to = 180°

60 + 75 + <RVE = 180°

135 + RVE = 180°

180 - 135 = 45° RVE

RVE = 45°

Another way to check your answer:

Add all of the angles, and it should equal 180°

60 + 75 + 45 = 180°

Correct!

6 0

3 years ago

Thomas wants to invite Madeline to a party. He has an 80% chance of bumping into her at school. Otherwise, he'll call her on the

mash [69]

Answer:

The probability of Thomas inviting Madeline to the party over the phone is 0.143.

Step-by-step explanation:

Consider the tree diagram below.

The events are denoted as follows:

A = Thomas bumps into Madeline at school

B = Thomas call Madeline on the phone

X = Thomas asks Madeline to the party

The information provided is:

P (A) = 0.80

P (B) = 1 - P (A) = 1 - 0.80 = 0.20

P (X|A) = 0.90

⇒ P (X'|A) = 1 - P (X|A) = 1 - 0.90 = 0.10

P (X|B) = 0.60

⇒ P (X'|B) = 1 - P (X|B) = 1 - 0.60 = 0.40

The conditional probability of event U given that another events V has already occurred is:

$P(U|V)=\frac{P(V|U)P(U)}{P(V)}$

The law of total probability states that:

$P(V)=P(V|U)P(U)+P(V|U')P(U')$

In this case we need to determine the probability that Thomas invites Madeline to the party over the phone, i.e. P (B|X).

Use the law of total probability to determine the value of P (X) as follows:

$P(X) = P(X|A)P(A)+P(X|B)P(B)$

$=(0.90\times 0.80)+(0.60\times 0.20)\\=0.72+0.12\\=0.84$

Compute the value of P (B|X) as follows:

$P(B|X)=\frac{P(X|B)P(B)}{P(X)}$

$=\farc{0.60\times 0.20}{0.84}\\\\=0.14286\\\\\approx 0.143$

Thus, the probability of Thomas inviting Madeline to the party over the phone is 0.143.

6 0

3 years ago