Complete Question
A set of magical wand prices are normally distributed with a mean of 50 dollars and a standard deviation of 4 dollars. A blackthorn wand has a price of 45.20. What proportion of wand prices are lower than the price of the blackthorn wand? You may round your answer to four decimal places
Answer:
0.1151
Step-by-step explanation:
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score = $45.20
μ is the population mean = $50
σ is the population standard deviation = $4
We are solving for x < 45.20
Hence:
z = 45.20 - 50/4
z = -1.2
Probability value from Z-Table:
P(x<45.20) = 0.11507
Approximately to 4 decimal places = 0.1151
Therefore, the proportion of wand prices that are lower than the price of the blackthorn wand is 0.1151
<span>3(x + 5) = 2(3x + 18)
Use the distributive property:
3(x)+5(3)=2(3x)+18(2)
Simplify:
3x+15=6x+36
6x+36=3x+15
3x+36=15
3x=-21
x=-7
Check answer:
3(-7+5)=2(-21+18)
3(-2)=2(-3)
-6=-6
Hope this helps :)
</span>
Answer:
9
Step-by-step explanation:
cuz i said
Answer:
$200
Step-by-step explanation:
4 different streets with 5 customers on each means 4*5 customers or 20 customers. If he has 20 customers and he gets $10 from each one, thats 20*10. he collected $200
Answer:
And we can calculate the p value with the following probability taking in count the alternative hypothesis:
And for this case using a significance level of 
we see that the p value is larger than the significance level so then we can conclude that we FAIL to reject the null hypothesis and we don't have enough evidence to conclude that the true proportion is less than 0.02
Step-by-step explanation:
For this case we want to test the following system of hypothesis:
Null hypothesis: 
Alternative hypothesis: 
The statistic for this case is given by:
(1)
And for this case we know that the statistic is given by:
And we can calculate the p value with the following probability taking in count the alternative hypothesis:
And for this case using a significance level of we see that the p value is larger than the significance level so then we can conclude that we FAIL to reject the null hypothesis and we don't have enough evidence to conclude that the true proportion is less than 0.02
