Answer:
A positive times a negative will always be a negative and when u divide a positive by a negative the same rules apply so it will be a negative 
 
        
             
        
        
        
The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:

Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt +  1.5/110 x 40 = 0
1/7 x dP/dt +  6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of  dP/dt is -42/11 kPa/min
Learn more about adiabatic expansion on:
brainly.com/question/6966596
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Answer:
<u>15</u>
<u>2x</u>
Step-by-step explanation:
 
        
             
        
        
        
Answer:
c
Step-by-step explanation:
C says that w must be greater than or equal to 452.2 and less than or equal to 455.0