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V125BC [204]
3 years ago
5

a right angle triangle has the perimeter of 96cm. the length of its sides are in the ratio of 6:8:10. work out the area of the t

riangle
Mathematics
2 answers:
deff fn [24]3 years ago
6 0

Answer:

Area = 384 cm²

Step-by-step explanation:

Perimeter = 96 cm

Ratio = 6:8:10

So,

6x+8x+10x = 96

=> 24x = 96

<u><em>Dividing both sides by 24</em></u>

=> x = 4

So, The sides are

=> 24 cm

=> 32 cm

=> 40 cm

<u><em>Now the area using Heron's Formula</em></u>

Area = \sqrt{s(s-a)(s-b)(s-c)}

Where s is the semi-perimeter = 48 cm, a , b and c are the sides

Area = \sqrt{48(48-24)(48-32)(48-40)}

Area = \sqrt{48(24)(16)(8)}

Area = \sqrt{147,456}

Area = 384 cm²

Solnce55 [7]3 years ago
4 0

Answer:

384 centimeters squared.

Step-by-step explanation:

96/(6+8+10)

96/24 = 4

6×4 : 8×4 : 10×4

24:32:40

The length of its sides are in the ratio of 24:32:40

The longest side is the hypotenuse which is 40.

The area is base × height × 1/2 of a triangle.

32 × 24 × 1/2

768 × 1/2

=384

The area of the triangle is 384 cm squared.

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marysya [2.9K]

The price of house is $185000.

Step-by-step explanation:

The percentage formula will be used for finding the price of the house

Given

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Percentage = 14%

Let x be the price of the home

Then

Down\ payment=14\%\ of\ x\\\\25900=0.14 * x\\\\x = \frac{25900}{0.14}\\\\x =185000

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The price of house is $185000.

Keywords: Down payment, percentage

Learn more about percentage at:

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5.C

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What is the x-intercept of the line with the equation 4x + 3y = 12?
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To find the x intercept replace y with 0 in the equation and solve for x:

4x +3(0) = 12

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3 years ago
Please help. Will give Brainliest!!
Natalija [7]

Answer:

9. <em><u>1</u></em><em><u>0</u></em>

10. <em><u>1</u></em><em><u>0</u></em><em><u>/</u></em><em><u>2</u></em><em><u>6</u></em>

11.<em><u>2</u></em><em><u>4</u></em><em><u>/</u></em><em><u>2</u></em><em><u>6</u></em>

12.<em><u>2</u></em><em><u>4</u></em><em><u>/</u></em><em><u>1</u></em><em><u>0</u></em>

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<em><u>=</u></em><em><u>></u></em><em><u> </u></em><em><u>P </u></em><em><u>=</u></em><em><u> </u></em><em><u>√</u></em><em><u>(</u></em><em><u>H</u></em><em><u>²</u></em><em><u>-</u></em><em><u>B</u></em><em><u>²</u></em><em><u>)</u></em>

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<em><u>P </u></em><em><u>=</u></em><em><u> </u></em><em><u>perpendicular</u></em><em><u> </u></em>

<em><u>B </u></em><em><u>=</u></em><em><u> </u></em><em><u>Base</u></em>

<em><u>H </u></em><em><u>=</u></em><em><u> </u></em><em><u>Hypotenuse</u></em>

<em><u>1</u></em><em><u>0</u></em><em><u>.</u></em><em><u> </u></em><em><u>P/</u></em><em><u>H</u></em>

<em><u>1</u></em><em><u>1</u></em><em><u>.</u></em><em><u> </u></em><em><u>B/</u></em><em><u>H</u></em>

<em><u>1</u></em><em><u>2</u></em><em><u>.</u></em><em><u> </u></em><em><u>P/</u></em><em><u>B</u></em>

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