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2 years ago

HELP MIDDLE SCHOOL QUESTION

Mathematics

1 answer:

OLga [1]2 years ago

7 0

1897 is how much he ran

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Solve this equation. Enter your answer in the box.<br> 13(y+7)=3(y−1).

Fofino [41]

★To Solve :

$\rm\blue{13(y+7) = 3(y-1)}$

⠀⠀⠀⠀⠀

★SOLUTION :

$\rm\red\leadsto{13(y+7) = 3(y-1)}$

$\rm\red\leadsto{13\times{y}+13\times7= 3\times{y}-3\times1}$

$\rm\red\leadsto{13y+91=3y-3}$

$\rm\red\leadsto{13y-3y=-3-91}$

$\rm\red\leadsto{10y=-94}$

$\rm\red\leadsto{} y =\dfrac{ { \cancel{-94}}^{ \:-45 } }{ { \cancel{10}}^{ \: 5} }$

$\rm\red\leadsto{y=}\dfrac{-47}{5}$

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5 0

3 years ago

Read 2 more answers

Which answer describes the transformation of f(x)=log2(x−5)−2 from the parent function g(x)=log2x ? A) It is the graph of g(x) s

damaskus [11]

Answer:

It is the graph of g(x) shifted 5 units right and 2 units down.

Step-by-step explanation:

Given : f(x)=log_2(x−5)−2

the parent function g(x)=log_2(x)

To get f(x) , 5 is subtracted from x

If we add any number with x then we shift left

If we subtract any number from x then we shift right

Here 5 is subtracted from x , so we shift 5 units right

Also -2 at the end

If we add any number at the end , then we shift up

if we subtract any number at the end , then we shift down

Here 2 is subtracted at the end , so we shift 2 units down

It is the graph of g(x) shifted 5 units right and 2 units down.

4 0

2 years ago

Consider m = y2 - y1/ x2 - x1 . Which x1 and x2-values would determine that the line is vertical? Justify your answer

Y_Kistochka [10]

Answer:

$x_2=x_1$

Step-by-step explanation:

We were given the slope formula;

$m=\frac{y_2-y_1}{x_2-x_1}$

This line is vertical if the denominator is zero.

That is when $x_2-x-1=0$

This implies that;

$x_2=x_1$

Justification;

When $x_2=x_1$ , then, the line passes through;

$(x_1,y_1)$ and $(x_1,y_2)$

The slope now become

$m=\frac{y_2-y_1}{x_1-x_1}=\frac{y_2-y_1}{0}$

The equation of the line is

$y-y_1=\frac{y_2-y_1}{0}(x-x_1)$

This implies that;

$0(y-y_1)=(y_2-y_1)(x-x_1)$

$0=(y_2-y_1)(x-x_1)$

$\frac{0}{y_2-y_1}=(x-x_1)$

$0=(x-x_1)$

$x=x_1$ ... This is the equation of a vertical line.

3 0

2 years ago

Which graph represents this equation?

zheka24 [161]

The graph in the bottom left is correct

5 0

2 years ago

Can anyone help me with this?

Illusion [34]

Answer:

Step-by-step explanation:

5 0

2 years ago