Answer:
y²/324 -x²/36 = 1
Step-by-step explanation:
Where (0, ±b) are the ends of the transverse axis and y = ±(b/a)x describes the asymptotes, the equation of the hyperbola can be written as ...
y²/b² -x²/a² = 1
<h3>Application</h3>
Here, we have transverse axis endpoints of (0, ±18) and asymptotes of y = ±3x, so we can conclude ...
b = 18
b/a = 3 ⇒ a = 18/3 = 6
The equation of the hyperbola in standard form is ...
y²/324 -x²/36 = 1
Since it is given that the reduction in the amount of waste each week is linear, it is conclusive that these data are also in arithmetic sequence. First, determine the common difference (d)
d = (a10 - a5) / (10 - 5)
Subsituting the known values,
d = (30 - 40) / 5 = -2
To determine any term (at) of the arithmetic sequence,
at = a1 + (n - 1) x d
Solve for a1 by using either the given a5 or a10,
40 = a1 + (5 -1) x -2 ; a1 = 48
The equation becomes,
at = 48 + -2(n -1)
Answer:
w⁴ + 3w³ + 11w² + 6w + 18
Step-by-step explanation:
Rectanle area = height * width
area = (w²+3w+9)(w² + 2)
= w²*w² + w²*2 + 3w*w² + 3w*2 + 9*w² + 9*2
= w⁴ + 2w² + 3w³ + 6w + 9w² + 18
= w⁴+ 3w³ + (9w²+2w²) + 6w + 18
= w⁴ + 3w³ + 11w² + 6w + 18
Half of 73 is 36.5 and I think the nearest half would be 37
<u><em>≡ Solution:</em></u>
<em>⇔ To make it easier:</em>
⇒ ²¹/₂₅ × ⁴/₄
⇒ ⁸⁴/₁₀₀
<u>⇒ 0,84</u>
