I think the answer is A. But I’m not fully sure
Statement 1: WXYZ is a kite
Reason 1: Given
Statement 2: WX = XY and WZ = YZ
Reason 2: Definition of a kite
Statement 3: XZ = XZ
Reason 3: Reflexive property
Statement 4: Triangle WXZ = Triangle YXZ
Reason 4: SSS Congruence
Statement 5: Angle W = Angle Y
Reason 5: CPCTC
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Extra notes:
* A kite is a quadrilateral that has two pairs of adjacent congruent sides. In this case, WX and XY is one pair of congruent sides that are adjacent (ie next to each other). So that's why WX = XY. Similarly, WZ = YZ is the second pair of adjacent congruent sides.
* Draw in a segment from point X to point Z to help form two triangles. The two triangles are congruent as proven in statement 4. One triangle is a reflection over the line XZ to get the other triangle.
* Due to this reflection, angle W reflects over line XZ to get angle Y. Proving that angle W = angle Y
* SSS means "side side side", basically saying "you use three pairs of congruent sides to prove two triangles congruent".
* The acronym CPCTC stands for "corresponding parts of congruent triangles are congruent"
Perimeter is 2l+2w in the case of a rectangle, so you would write:
2(4x - 4.25) + 2(7x +7)
Answer:
3. 294 m²
4. 185,856 mm²
Step-by-step explanation:
To find the surface area of any figure, you can simply find the sum of the areas of all the sides. In question 3, the figure is a triangular prism that has two triangular bases and three rectangular sides. The measurements for the triangles are b = 9m and h = 6m. The formula for the area of a triangle is base times height divided by 2, or 9 x 6 = 54/2 = 27 m². However, since there are two triangular bases, the area for both is 54 m². The measurements for the other three rectangles are given:
7(10) + 8(10) + 9(10) = 240 m² + 54 m² = 294 m²
The surface area of a cube is much easier since all sides are equal and can be found using the formula:
SA = 6s², where 's' represents the measure of a side.
SA = 6(176)² = 185,856 mm²
Answer:
x=2
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.