Answer:
2nd Option is correct that is ∠T and ∠P.
Step-by-step explanation:
We are given that ΔGET ≅ ΔMAP
We need to find Congruent part from the given options.
Since, we are given the figure of the congruent triangles with marking not any instruction with which vertex is congruent to which vertex.
So, The Given Name of the Congruent triangle.
We deduce that
G ↔ M
E ↔ A
T ↔ P
Using this we get following congruent parts,
GE ≅ MA , GT ≅ MP and ET ≅ AP
∠G ≅ ∠M , ∠E ≅ ∠A and ∠T ≅ ∠P.
Therefore, 2nd Option is correct that is ∠T and ∠P.
Answer:
Perimeter = 36 units
Step-by-step explanation:
The figure given has been labelled with letters for easy reference.
Recall: when two tangents segments meet at a point outside the circle, the two segments that are tangent to the circle are congruent to each.
Perimeter = a + b + c + d + e + f
e = 4 (given)
e = f = 4 (tangents drawn from an external point)
b = 10 - f
Substitute
b = 10 - 4
b = 6
b = a = 6 (tangents drawn from an external point)
c = 8 (given)
c = d = 8 (tangents drawn from an external point)
Perimeter = 6 + 6 + 8 + 8 + 4 + 4
Perimeter = 36 units
15x-3y=12
<u>y=5x—4
</u>I'm also not sure what your question is, but this is what I got by solving it like a regular equation.
15x-3(5x-4)=12
15x-15x+12=12
0=12-12
0=0
4x-y=-4
<span><u>-8x+2y=2</u>
</span>
-y=-4-4x /: (-1)
y=4+4x
-8x+2y=2
-8x+2(4+4x)=2
-8x+8+8x=2
0=-6
The answer is going to be s. The proportions are (short leg/long leg) , and the appropriate long leg for h is s.
Answer:
2
Step-by-step explanation:
Experimental probability : (Number of times event occur / total number of trials)
Total Number of trials = (3 + 4 + 6 + 3) = 16
Experimental probability :
For 1: P(1) :
3/16
For 2 : P(2) :
4/16 = 1/4
For 3: P(3)
6 /16 = 3/8
For 4 : P(4)
3 / 16
Theoretical probability :
The Theoretical probability of 1, 2, 3 and 4 are the same ;
Theoretical probability =
(Required outcome / Total possible outcomes)
For each of 1 - 4
Theoretical probability = 1 /4
Experimental probability of P(2) = 1/ 4 and is Hence, the same as the Theoretical probability