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3 years ago

Can someone help me solve for x & explain how they got it please?? i have a test tomorrow!!

Mathematics

2 answers:

Fudgin [204]3 years ago

8 0

Answer:

36=x^2+5x

x^2+5x-36=0

(x+9)(x-4)

x= 4

x= -9

The Answer can be 4 or -9, see which option you have.

Step-by-step explanation:

amid [387]3 years ago

7 0

Answer:

x=4

Step-by-step explanation:

Usually what I do is sort of a guess and check, and this should be easy if your square roots memorized

First you know that x^2+5x is equaled to 36 because both sides of the triangle has a tick

I look at x squared first. You know the value for X has to be less than six because 6 squared is already 36.

Then I start plugging in values under 6 like 5, 4, 3 ex

When you plug in 5 you get 50, so we know we have to choose a lower value

When plugging in 4 you get 36

4 squared is 16, 5 x 4 = 20, 20+16 = 36

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The function Q(x)=2x^2-kx+18. For what value of k does Q(x) have one distinct real solution? (NEEDS TO BE DONE WITHIN 2 HOURS!)

Aliun [14]

Answer:

k = 12

Step-by-step explanation:

Given:

The equation $Q(x)=2x^2-kx+18$

To find:

Value of $k = ?$ for which the given equation has one distinct real solution.

Solution:

The given equation is a quadratic equation.

There are always two solutions of a quadratic equation.

For the equation: $ax^{2} +bx+c=0$ to have one distinct solution:

$b^2 - 4ac = 0$

Here,

a = 2,

b = -k and

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Putting the values, we get:

$(-k)^2 - 4\times 2\times 18 = 0\\\Rightarrow k^2 = 18\times 8\\\Rightarrow k^2 =144\\\Rightarrow k = 12$

The equation becomes:

$Q(x)=2x^2-12x+18$

And the one root is:

$2(x^2-6x+9 ) = 0\\\Rightarrow 2(x-3)^2=0\\\Rightarrow x = 3$

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Step-by-step explanation:

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